GRADE 8 PRACTICE
Physics Problems: Electric current, Grade 8
Sources, circuits, current and voltage.
Here the conditions and analysis of the solution can be read without an account. In the simulator, you need to collect the same analyzes yourself: “Given,” formulas, order of steps and answer.
Problem statements
The answer options are there to check against, and the walkthrough opens under each problem.
Problem #37
Electric current and circuitWhat concept does the description correspond to: “Ordered motion of charged particles, requiring mobile carriers and an electric field.»?
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- \text{Description}
- \text{Ordered motion of charged particles, requiring mobile carriers and an electric field.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
In metals, carriers are electrons; conventional current direction is opposite to their directed motion.
- \text{Let's formulate conclusion}\text{Concept} = \text{Electric current}
Answer\text{Concept} = \text{Electric current}
Problem #38
Electric current and circuitWhat concept does the description correspond to: “A device that separates charges by converting chemical, mechanical, light or other energy.»?
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- \text{Description}
- \text{A device that separates charges by converting chemical, mechanical, light or other energy.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
The source maintains a potential difference, and the closed circuit provides a charge path. Read its diagram using standard component symbols.
- \text{Let's formulate conclusion}\text{Concept} = \text{Electrical source}
Answer\text{Concept} = \text{Electrical source}
Problem #39
Electric currentThere are free electrons in a metal wire. What additional condition is necessary for a stable current?
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- \text{carriers}
- \text{free electrons}
\text{second condition current} - ?
- \text{free carriers without fields moving chaotically}
- \text{Field creates directed component movement}\text{needed field and closed chain}
Answer\text{electric field B closed chains}
Problem #40
Current, voltage and measuring instrumentsWhat concept does the description correspond to: “A physical quantity equal to the charge passing through the cross section of a conductor per unit time.»?
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- \text{Description}
- \text{A physical quantity equal to the charge passing through the cross section of a conductor per unit time.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
The ammeter is connected in series so that the same current passes through it as through the element under study.
- \text{Let's formulate conclusion}\text{Concept} = \text{Electric current}
Answer\text{Concept} = \text{Electric current}
Problem #41
Current, voltage and measuring instrumentsWhat concept does the description correspond to: “A physical quantity equal to the work done by an electric field to transfer a unit charge.»?
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- \text{Description}
- \text{A physical quantity equal to the work done by an electric field to transfer a unit charge.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
A voltmeter is connected in parallel across a section because it compares the electrical states at its two ends.
- \text{Let's formulate conclusion}\text{Concept} = \text{Electrical voltage}
Answer\text{Concept} = \text{Electrical voltage}
Problem #42
Electric current120 C of charge passed through the cross section of the conductor in 60 s. Find the current.
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- q
- 120\,\text{Кл}
- t
- 60\,\text{с}
I - ?
- I=\frac{q}{t}I=\frac{120}{60}\,\text{А}I = 2\,\text{А}
Answer2\,\text{А}
Problem #145
Electric current and circuitVia transverse section conductor for 20 s charge passed 60 class Find force current.
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- t
- 20\,\text{с}
- q
- 60\,\text{Кл}
I - ?
- I=\frac{q}{t}I=\frac{60}{20}I=3\,\text{А}
Current shows the charge passed per unit of time.
Answer3\,\text{А}
Problem #146
Electric current and circuitVia transverse section conductor for 30 s charge passed 120 class Find force current.
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- t
- 30\,\text{с}
- q
- 120\,\text{Кл}
I - ?
- I=\frac{q}{t}I=\frac{120}{30}I=4\,\text{А}
Current shows the charge passed per unit of time.
Answer4\,\text{А}
Problem #147
Electric current and circuitElectric current 0{,}5 A constant B current 4 min. Which charge passed by chains?
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- I
- 0{,}5\,\text{А}
- t
- 4\,\text{мин}
q - ?
- T=60tT=4 \cdot 60T=240\,\text{с}
Convert minutes to seconds.
- q=ITq=0{,}5 \cdot 240q=120\,\text{Кл}
With constant current, charge is proportional to time.
Answer120\,\text{Кл}
Problem #148
Electric current and circuitElectric current 0{,}8 A constant B current 5 min. Which charge passed by chains?
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- I
- 0{,}8\,\text{А}
- t
- 5\,\text{мин}
q - ?
- T=60tT=5 \cdot 60T=300\,\text{с}
Convert minutes to seconds.
- q=ITq=0{,}8 \cdot 300q=240\,\text{Кл}
With constant current, charge is proportional to time.
Answer240\,\text{Кл}
Problem #149
Electric current and circuitB first 20 with by chains passed current 2 A, then B current 40 with current 5 A. Find average force current for everything time.
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- t_1
- 20\,\text{с}
- I_1
- 2\,\text{А}
- t_2
- 40\,\text{с}
- I_2
- 5\,\text{А}
I_{\text{ср}} - ?
- q_1=I_1t_1q_1=2 \cdot 20q_1=40\,\text{Кл}
Find the charge of the first gap.
- q_2=I_2t_2q_2=5 \cdot 40q_2=200\,\text{Кл}
Find the charge of the second gap.
- I_{\text{ср}}=\frac{q_1+q_2}{t_1+t_2}I_{\text{ср}}=\frac{(40 + 200)}{(20 + 40)}I_{\text{ср}}=4\,\text{А}
We divide the entire charge for the entire time.
Answer4\,\text{А}
Problem #150
Electric current and circuitB first 30 with by chains passed current 3 A, then B current 30 with current 7 A. Find average force current for everything time.
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- t_1
- 30\,\text{с}
- I_1
- 3\,\text{А}
- t_2
- 30\,\text{с}
- I_2
- 7\,\text{А}
I_{\text{ср}} - ?
- q_1=I_1t_1q_1=3 \cdot 30q_1=90\,\text{Кл}
Find the charge of the first gap.
- q_2=I_2t_2q_2=7 \cdot 30q_2=210\,\text{Кл}
Find the charge of the second gap.
- I_{\text{ср}}=\frac{q_1+q_2}{t_1+t_2}I_{\text{ср}}=\frac{(90 + 210)}{(30 + 30)}I_{\text{ср}}=5\,\text{А}
We divide the entire charge for the entire time.
Answer5\,\text{А}
Problem #151
Current, voltage and measuring instrumentsVia transverse section conductor for 20 s charge passed 60 class Find force current.
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- t
- 20\,\text{с}
- q
- 60\,\text{Кл}
I - ?
- I=\frac{q}{t}I=\frac{60}{20}I=3\,\text{А}
Current shows the charge passed per unit of time.
Answer3\,\text{А}
Problem #152
Current, voltage and measuring instrumentsVia transverse section conductor for 30 s charge passed 120 class Find force current.
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- t
- 30\,\text{с}
- q
- 120\,\text{Кл}
I - ?
- I=\frac{q}{t}I=\frac{120}{30}I=4\,\text{А}
Current shows the charge passed per unit of time.
Answer4\,\text{А}
Problem #153
Current, voltage and measuring instrumentsElectric current 0{,}5 A constant B current 4 min. Which charge passed by chains?
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- I
- 0{,}5\,\text{А}
- t
- 4\,\text{мин}
q - ?
- T=60tT=4 \cdot 60T=240\,\text{с}
Convert minutes to seconds.
- q=ITq=0{,}5 \cdot 240q=120\,\text{Кл}
With constant current, charge is proportional to time.
Answer120\,\text{Кл}
Problem #154
Current, voltage and measuring instrumentsElectric current 0{,}8 A constant B current 5 min. Which charge passed by chains?
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- I
- 0{,}8\,\text{А}
- t
- 5\,\text{мин}
q - ?
- T=60tT=5 \cdot 60T=300\,\text{с}
Convert minutes to seconds.
- q=ITq=0{,}8 \cdot 300q=240\,\text{Кл}
With constant current, charge is proportional to time.
Answer240\,\text{Кл}
Problem #155
Current, voltage and measuring instrumentsB first 20 with by chains passed current 2 A, then B current 40 with current 5 A. Find average force current for everything time.
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- t_1
- 20\,\text{с}
- I_1
- 2\,\text{А}
- t_2
- 40\,\text{с}
- I_2
- 5\,\text{А}
I_{\text{ср}} - ?
- q_1=I_1t_1q_1=2 \cdot 20q_1=40\,\text{Кл}
Find the charge of the first gap.
- q_2=I_2t_2q_2=5 \cdot 40q_2=200\,\text{Кл}
Find the charge of the second gap.
- I_{\text{ср}}=\frac{q_1+q_2}{t_1+t_2}I_{\text{ср}}=\frac{(40 + 200)}{(20 + 40)}I_{\text{ср}}=4\,\text{А}
We divide the entire charge for the entire time.
Answer4\,\text{А}
Problem #156
Current, voltage and measuring instrumentsB first 30 with by chains passed current 3 A, then B current 30 with current 7 A. Find average force current for everything time.
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- t_1
- 30\,\text{с}
- I_1
- 3\,\text{А}
- t_2
- 30\,\text{с}
- I_2
- 7\,\text{А}
I_{\text{ср}} - ?
- q_1=I_1t_1q_1=3 \cdot 30q_1=90\,\text{Кл}
Find the charge of the first gap.
- q_2=I_2t_2q_2=7 \cdot 30q_2=210\,\text{Кл}
Find the charge of the second gap.
- I_{\text{ср}}=\frac{q_1+q_2}{t_1+t_2}I_{\text{ср}}=\frac{(90 + 210)}{(30 + 30)}I_{\text{ср}}=5\,\text{А}
We divide the entire charge for the entire time.
Answer5\,\text{А}
The theory behind these problems
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Formulas by topic
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