GRADE 9 PRACTICE
Physics Problems: Mechanical waves and sound, Grade 9
Types of waves, length, speed, properties and perception of sound.
Here the conditions and analysis of the solution can be read without an account. In the simulator, you need to collect the same analyzes yourself: “Given,” formulas, order of steps and answer.
Problem statements
The answer options are there to check against, and the walkthrough opens under each problem.
Problem #34
Mechanical wavesWhat concept does the description correspond to: “In a longitudinal wave, particles oscillate along the propagation, and in a transverse wave, particles oscillate perpendicular to it.”?
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- \text{Description}
- \text{In a longitudinal wave, particles oscillate along the propagation direction; in a transverse wave, they oscillate perpendicular to it.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
Sound in a gas is longitudinal, while a wave on a taut string is transverse in the simple model.
- \text{Let's formulate conclusion}\text{Concept} = \text{Longitudinal and transverse waves}
Answer\text{Concept} = \text{Longitudinal and transverse waves}
Problem #35
Mechanical wavesWhat concept does the description correspond to: “Propagation of vibrations and energy in an elastic medium without transfer of matter over long distances.”?
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- \text{Description}
- \text{Propagation of vibrations and energy in an elastic medium without transfer of matter over long distances.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
Particles of the medium oscillate about equilibrium, passing the disturbance to their neighbours.
- \text{Let's formulate conclusion}\text{Concept} = \text{Mechanical wave}
Answer\text{Concept} = \text{Mechanical wave}
Problem #36
Mechanical wavesThe wave travels at a speed of 340 m/s and has a frequency of 170 Hz. Find the wavelength.
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- v
- 340\,\text{м/с}
- \nu
- 170\,\text{Гц}
\lambda - ?
- v=\lambda\nu
- \lambda=\frac{v}{\nu}\lambda=\frac{340}{170}\,\text{м}\lambda = 2\,\text{м}
Answer2\,\text{м}
Problem #37
Sound, echo and resonanceWhat concept does the description correspond to: “Pitch is mainly related to frequency, loudness is related to intensity, and timbre is related to the spectral composition of sound.”?
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- \text{Description}
- \text{Pitch is mainly related to frequency, loudness to intensity, and timbre to the sound's spectral composition.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
The same note played by different instruments differs in timbre because their overtones differ.
- \text{Let's formulate conclusion}\text{Concept} = \text{Pitch, loudness and timbre}
Answer\text{Concept} = \text{Pitch, loudness and timbre}
Problem #38
Sound, echo and resonanceWhat concept does the description correspond to: “Infrasound has a frequency below the human audible range, and ultrasound has a frequency above it.”?
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- \text{Description}
- \text{Infrasound has a frequency below the human audible range, and ultrasound has a frequency above it.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
Ultrasound is used in diagnosis and echolocation, with attention to intensity and exposure safety.
- \text{Let's formulate conclusion}\text{Concept} = \text{Infrasound and ultrasound}
Answer\text{Concept} = \text{Infrasound and ultrasound}
Problem #39
soundThe echo returned after 0.8 seconds. Speed of sound 340 m/s. Find the distance to the obstacle.
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- t
- 0{,}8\,\text{с}
- v
- 340\,\text{м/с}
s - ?
- s=\frac{vt}{2}s=\frac{340\cdot0{,}8}{2}\,\text{м}s = 136\,\text{м}
Answer136\,\text{м}
Problem #130
Mechanical wavesWave speed 12 m/s, frequency 3 Hz Find the wavelength.
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- v
- 12\,\text{м/с}
- f
- 3\,\text{Гц}
\lambda - ?
- \lambda=\frac{v}{f}\lambda=\frac{12}{3}\lambda=4\,\text{м}
In one period, a wave travels one wavelength.
Answer4\,\text{м}
Problem #131
Mechanical wavesWave speed 20 m/s, frequency 5 Hz Find the wavelength.
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- v
- 20\,\text{м/с}
- f
- 5\,\text{Гц}
\lambda - ?
- \lambda=\frac{v}{f}\lambda=\frac{20}{5}\lambda=4\,\text{м}
In one period, a wave travels one wavelength.
Answer4\,\text{м}
Problem #132
Mechanical wavesWavelength 0{,}5 m, for 10 with source committed 40 hesitation. Find the speed of the wave.
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- l
- 0{,}5\,\text{м}
- t
- 10\,\text{с}
- N
- 40\,\text{колебаний}
v - ?
- f=\frac{N}{t}f=\frac{40}{10}f=4\,\text{Гц}
Find the frequency of the source.
- v=\lambda fv=0{,}5 \cdot 4v=2\,\text{м/с}
The frequency of the wave matches the frequency of the source.
Answer2\,\text{м/с}
Problem #133
Mechanical wavesWavelength 0{,}8 m, for 20 with source committed 50 hesitation. Find the speed of the wave.
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- l
- 0{,}8\,\text{м}
- t
- 20\,\text{с}
- N
- 50\,\text{колебаний}
v - ?
- f=\frac{N}{t}f=\frac{50}{20}f=2{,}5\,\text{Гц}
Find the frequency of the source.
- v=\lambda fv=0{,}8 \cdot 2{,}5v=2\,\text{м/с}
The frequency of the wave matches the frequency of the source.
Answer2\,\text{м/с}
Problem #134
Mechanical wavesIn the first medium the wave speed 12 m/s, length 3 m. In the second environment the speed 8 m/s. How many wavelengths of the second medium fit at a distance 20 m? The frequency at the border does not change.
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- v_1
- 12\,\text{м/с}
- l_1
- 3\,\text{м}
- v_2
- 8\,\text{м/с}
- S
- 20\,\text{м}
N - ?
- f=\frac{v_1}{\lambda_1}f=\frac{12}{3}f=4\,\text{Гц}
First we find a constant frequency.
- \lambda_2=\frac{v_2}{f}\lambda_2=\frac{8}{4}\lambda_2=2\,\text{м}
In the second medium the wavelength changes.
- N=\frac{S}{\lambda_2}N=\frac{20}{2}N=10\,\text{длин волн}
Divide the distance by the new wavelength.
Answer10\,\text{длин волн}
Problem #135
Mechanical wavesIn the first medium the wave speed 20 m/s, length 4 m. In the second environment the speed 10 m/s. How many wavelengths of the second medium fit at a distance 30 m? The frequency at the border does not change.
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- v_1
- 20\,\text{м/с}
- l_1
- 4\,\text{м}
- v_2
- 10\,\text{м/с}
- S
- 30\,\text{м}
N - ?
- f=\frac{v_1}{\lambda_1}f=\frac{20}{4}f=5\,\text{Гц}
First we find a constant frequency.
- \lambda_2=\frac{v_2}{f}\lambda_2=\frac{10}{5}\lambda_2=2\,\text{м}
In the second medium the wavelength changes.
- N=\frac{S}{\lambda_2}N=\frac{30}{2}N=15\,\text{длин волн}
Divide the distance by the new wavelength.
Answer15\,\text{длин волн}
Problem #136
Sound, echo and resonanceThe echo came back through 0{,}4 s after a short sound. Speed of sound 340 m/s. Find the distance to the reflective wall.
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- t
- 0{,}4\,\text{с}
- v
- 340\,\text{м/с}
S - ?
- S=\frac{vt}{2}S=\frac{340 \cdot 0{,}4}{2}S=68\,\text{м}
The sound travels the distance to the wall twice.
Answer68\,\text{м}
Problem #137
Sound, echo and resonanceThe echo came back through 0{,}6 s after a short sound. Speed of sound 340 m/s. Find the distance to the reflective wall.
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- t
- 0{,}6\,\text{с}
- v
- 340\,\text{м/с}
S - ?
- S=\frac{vt}{2}S=\frac{340 \cdot 0{,}6}{2}S=102\,\text{м}
The sound travels the distance to the wall twice.
Answer102\,\text{м}
Problem #138
Sound, echo and resonanceThe echo sounder signal returned after 80 ms. Speed of sound in water 1500 m/s. Find the depth.
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- t
- 80\,\text{мс}
- v
- 1500\,\text{м/с}
h - ?
- T=\frac{t}{1000}T=\frac{80}{1000}T=0{,}08\,\text{с}
Convert milliseconds to seconds.
- h=\frac{vT}{2}h=\frac{1500 \cdot 0{,}08}{2}h=60\,\text{м}
From the full round trip we get the depth.
Answer60\,\text{м}
Problem #139
Sound, echo and resonanceThe echo sounder signal returned after 120 ms. Speed of sound in water 1500 m/s. Find the depth.
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- t
- 120\,\text{мс}
- v
- 1500\,\text{м/с}
h - ?
- T=\frac{t}{1000}T=\frac{120}{1000}T=0{,}12\,\text{с}
Convert milliseconds to seconds.
- h=\frac{vT}{2}h=\frac{1500 \cdot 0{,}12}{2}h=90\,\text{м}
From the full round trip we get the depth.
Answer90\,\text{м}
Problem #140
Sound, echo and resonanceA man is between two walls. The first echo returned through 0{,}2 s, second through 0{,}5 s. Find the distance between the walls. Speed of sound 340 m/s; the first reflections from each wall are taken into account.
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- t_1
- 0{,}2\,\text{с}
- t_2
- 0{,}5\,\text{с}
- v
- 340\,\text{м/с}
S - ?
- S_1=\frac{vt_1}{2}S_1=\frac{340 \cdot 0{,}2}{2}S_1=34\,\text{м}
Find the distance to the nearest wall.
- S_2=\frac{vt_2}{2}S_2=\frac{340 \cdot 0{,}5}{2}S_2=85\,\text{м}
The second echo gives the distance to the other wall.
- S=S_1+S_2S=34 + 85S=119\,\text{м}
A person is between the walls, so the distances add up.
Answer119\,\text{м}
Problem #141
Sound, echo and resonanceA man is between two walls. The first echo returned through 0{,}3 s, second through 0{,}7 s. Find the distance between the walls. Speed of sound 340 m/s; the first reflections from each wall are taken into account.
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- t_1
- 0{,}3\,\text{с}
- t_2
- 0{,}7\,\text{с}
- v
- 340\,\text{м/с}
S - ?
- S_1=\frac{vt_1}{2}S_1=\frac{340 \cdot 0{,}3}{2}S_1=51\,\text{м}
Find the distance to the nearest wall.
- S_2=\frac{vt_2}{2}S_2=\frac{340 \cdot 0{,}7}{2}S_2=119\,\text{м}
The second echo gives the distance to the other wall.
- S=S_1+S_2S=51 + 119S=170\,\text{м}
A person is between the walls, so the distances add up.
Answer170\,\text{м}
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