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GRADE 8 · ELECTROMAGNETIC INDUCTION

Generators and electrical energy transmission

Conversion of mechanical energy and transmission with changes in voltage.

24 minutes7 theory cards
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Read the full lesson theory here without an account. In the interactive lesson, the same theory is presented as cards, followed by questions with feedback and practice problems. Your progress is saved.

Understanding step by step

A turbine turns a generator, and voltage is raised before energy enters a long transmission line. What does rotation do, and why does raising voltage help the wires heat up less?

Energy's path from the stationgeneratorraise Ulinehigher voltage — lower currentand less wire heatingAt the same transmitted power
The station drives the generator, then voltage is raised before the long-distance line. For the same transmitted power to a resistive load, the line carries less current and loses less heat at unchanged resistance. Icons represent stages of energy transmission.

Rotation changes flux

A loop rotates in a magnetic field, continuously changing its orientation. Even with constant B, the flux through the loop changes and a periodic emf arises. This is a simple generator model: a device that converts mechanical work into electrical energy by induction. A magnet can also rotate relative to the windings; what matters is a change in their linked flux. A strong stationary magnet alone cannot provide a continuous energy output.

View along the rotation axisNSBaxisOrientation changes → flux changes
View along the rotation axis: the loop is seen edge-on. The dashed line shows one position and the tilted solid segment shows another position of the same loop. The axis is perpendicular to the picture and B points right. Rotation changes the angle between the loop's normal and the field, so flux changes and an emf arises. Mechanical work comes from outside; the load and current collectors are not shown.

Current reverses direction

After half a turn, the flux changes in the opposite sense and the induced voltage reverses. A simple closed circuit with a load therefore carries alternating current. When the generator supplies energy, the induced action opposes rotation. A turbine or another motor must therefore keep driving the shaft. Once the mechanical energy input stops, the previous rotation cannot power the load forever.

Alternating voltage+−Utcurrent reverses directionrotation must be maintained
As the loop rotates, the generator voltage rises and reverses sign, so current in a closed resistive load periodically reverses. The sine wave is qualitative, with no numerical scale; continuous energy output requires mechanical work input.

Two coupled coils

A transformer changes voltage. Alternating current in its primary winding creates a changing magnetic flux in a shared core. This flux also passes through the secondary winding, inducing an emf there. The windings need not have any conducting contact: their coupling is magnetic. Electrons therefore do not need to move from one coil to the other for energy to reach a load connected to the secondary.

N₁N₂U₁ ~U₂ ~One closed coreWindings are electrically isolated
The continuous primary winding connects to an AC source. The secondary has separate terminals and is not electrically connected to the primary. Both wind around limbs of the same closed core; alternating flux induces a secondary emf. Turns are schematic. For an ideal transformer, U₁/U₂=N₁/N₂ when both voltages are of the same kind.

Why steady direct current is unsuitable

Replace the alternating current with steady direct current. At switch-on the field changes, so a brief effect is possible; then the flux becomes constant. An ordinary transformer no longer sustains a secondary voltage by this mechanism. Moreover, an unsuitable DC voltage supply can cause excessive current and overheating in the primary winding. A core and two coils therefore cannot replace the requirement for changing flux.

Alternating currentDirect currentchanging fluxItsecondaryhas Uconstant fluxItsecondaryno UAn unsuitable source may overheat the winding
Alternating current in the primary keeps changing the flux, so the secondary has voltage. The right-hand diagram shows steady direct current: the flux is constant, so there is no secondary voltage. An unsuitable DC source can cause overheating; switch-on and the transient are not shown here.

Voltage and turns

Each turn linked by the same changing flux contributes to the winding voltage. In the ideal model these contributions add: U₁/U₂ = N₁/N₂. Voltages U₁ and U₂ are measured in V; turn counts N₁ and N₂ are dimensionless. At fixed U₁, doubling N₂/N₁ doubles U₂; equal turn counts give equal voltages. The model neglects losses and voltage drops in the windings; it does not promise to create energy.

U₁ : U₂ = N₁ : N₂N₁N₂U₁U₂turnsvoltageMore turns → U rises by the same factorTurn count is a number without units
An ideal transformer's voltages have the same ratio as its turn counts: increasing the secondary turns by a factor increases its voltage by the same factor, for U values of the same kind. The bars on two separate scales illustrate a 1:3 ratio; do not compare N heights with U heights.

What an alternating U value means

How can one number describe voltage that changes continuously? Mains problems usually use the root mean square (RMS) value: a constant voltage of that size would produce the same average heating power in the same resistor. It is not the maximum instantaneous value. A transformer's voltage ratio must compare values of the same kind, such as two RMS values. Otherwise the ratio would silently mix different measurement conventions.

RMS valuealternating URsame heatingconstant URsame heatingSame heating — same U value
Across identical resistors R, an AC voltage's RMS value and an equal DC voltage produce the same average heating power. Both plots have the same vertical scale; for the sinusoid shown, the constant level equals the amplitude divided by √2. The graphs show voltage across the resistors.

Why use high voltage?

The transmission line also has resistance Rлинии. At a given current it dissipates power I²Rлинии that does not reach the consumer. In a simple resistive-load model, transmitted power is UI. Keeping power fixed while raising U reduces I and therefore wire heating. Simply raising the voltage across the same unchanged resistor would instead increase current. The benefit applies specifically to transmitting the same power.

Same power to a resistive loadstationstep upUhigh Utransformerstep down ULower I → lower line I²R
Energy transmission stages: voltage is raised after the generator for the long-distance line and lowered before the consumer. For the same power delivered to a resistive load, a higher U allows a smaller I; with unchanged line resistance, I²R losses decrease. Arrows connect stages and do not depict electrical connections.

How much losses fall

Reduce line current by a factor of 10 at unchanged resistance: (I/10)²R = I²R/100. Losses become 100 times smaller. A transformer matches a higher voltage with a smaller current for the same power; it adds no energy. Input and output powers are equal in an ideal transformer; a real one loses some energy. Voltage cannot be raised without limit: line construction and insulation are designed for specified conditions.

Losses fall faster than currentcurrent 10 times smallerthe formula contains I²line losses 100 times smallera transformer adds no energy
Line losses grow with the square of current, so reducing current tenfold reduces wire heating a hundredfold at the same line resistance.

Voltage is reduced near the consumer

The consumer needs the voltage specified for the equipment, so transformers reduce it near the point of use. The conversion chain is: mechanical work → generator → voltage change → line → voltage reduction → appliance. Domestic mains voltage is still dangerous to touch. It is reduced to suit the equipment, not to make touching conductors permissible.

Step down before the applianceslinehigh Usteps downdeviceoperating Uoperating does not mean safe to touchdo not touch live wiresMains voltage is dangerous to people
Before appliances are connected, voltage is reduced to their operating value. That value suits the equipment, but live wires must still not be touched.

Turns ratio

An ideal transformer has N₁ = 100, N₂ = 500 and RMS U₁ = 12 В. Find RMS U₂.

Ideal transformerN₁ = 100N₂ = 500U₁ = 12 ВU₂ — ?U₁ and U₂ are RMS valuesFind U₂
Ideal transformer: N₁=100, N₂=500, RMS U₁=12 В. The primary connects to an AC source; the secondary voltage is measured between two free terminals. Both windings share one core. Turns are drawn schematically; labels give the actual counts.

Worked example · 1

The secondary has 500 turns compared with 100: N₂/N₁ = 5. With the shared flux, its voltage is five times greater.

Compare the turn countsN₁ = 100N₂ = 500U₁ = 12 ВU₂ — ?N₂ / N₁ = 500 / 100 = 5Secondary: 5 times as many turns
The same transformer's secondary has five times as many turns: N₂/N₁=500/100=5. The common core, source and terminals are unchanged. Turns are schematic; labels specify their counts.

Worked example · 2

From U₁/U₂ = N₁/N₂ we obtain U₂ = U₁·N₂/N₁ = 12·5 = 60 В. Both the given voltage and the voltage sought are RMS values.

Calculate the voltageN₁ = 100N₂ = 500U₁ = 12 ВU₂ = 60 ВU₂ = U₁ · N₂ / N₁ = 12 · 5U₂ = 60 В, RMS
For the same ideal transformer, U₂=U₁·N₂/N₁=12 В·5=60 В. This is an RMS value, like the given U₁. Geometry and schematic turns are unchanged; the answer is the voltage between the secondary terminals.

Worked example · 3

Five times the voltage does not mean five times the power. In an ideal transformer, output energy comes from input energy; at a given power, the available current is correspondingly smaller.

A transformer does not create energyN₁ = 100N₂ = 500U₁ = 12 ВU₂ = 60 ВWith a load: U₁I₁ = U₂I₂U₂ = 5U₁ → I₂ = I₁ / 5
Voltage between the same secondary terminals is five times greater. No load is connected in the diagram: an output voltage alone does not mean power is being delivered. With a resistive load connected, the ideal transformer transmits the same power; the corresponding secondary current is five times smaller than the primary current.

Check the result

U₂ = 60 В. This is the RMS secondary voltage of an ideal transformer with a fivefold turns ratio.

Key idea · 1

A generator transfers energy supplied by mechanical work to a load through changing magnetic flux.

Key idea · 2

A transformer couples its windings through a changing field; their voltage ratio is set by their turns ratio.

Key idea · 3

For the same transmitted power, raising voltage reduces current and lowers line losses according to the square of current.

What comes next

Light can also carry energy. We will begin optics with light sources and how objects become visible.

Basic Concepts

3 concepts

Electrical energy transmission

Energy is transferred through wires at high voltage to reduce current and heat loss.

The transformer reduces the voltage to the operating value specified for the equipment. Household mains voltage remains dangerous for humans.

Electric generator

A device that converts mechanical rotational energy into electrical energy through electromagnetic induction.

Rotation of a coil or magnet periodically changes the flux and creates an alternating voltage.

Transformer

An AC device that changes voltage using two coils on a shared magnetic core.

The voltage ratio of an ideal transformer is equal to the ratio of the number of turns of its windings.

Physical quantities

3 quantities

Primary voltage

U_1

Voltage on the primary winding of the transformer.

Unit: volt · \mathrm{В}

Secondary voltage

U_2

Voltage on the secondary winding of the transformer.

Unit: volt · \mathrm{В}

Number of winding turns

N

The number of turns of wire in the selected transformer winding.

Unit: dimensionless quantity

Lesson formulas

1 formula

Ideal transformer

\frac{U_1}{U_2}=\frac{N_1}{N_2}

The voltage ratio is equal to the ratio of the number of turns of the primary and secondary windings.

Conditions: An ideal transformer with a shared alternating magnetic flux; losses and voltage drops in the windings are neglected. U₁ and U₂ must be values of the same kind, for example both RMS.

Test the relationship

Make a prediction first. The button changes the stated quantity; then compare the result and explore other values.

Rotating coil and emf

Φ = BS cos(ωt); ε = −N dΦ/dt = NBSω sin(ωt); N = 100

100 identical turns in a uniform field; constant rotation rate. Φ is flux through one turn. The circuit is open; current and reaction torque are not modelled.

Rotation frequency increases from 1 to 2 Hz. How will the emf amplitude change?

Your prediction

Initial values

Show vectors
nBN = 100; Φ = BS cos(ωt)
0-15.580.5-7.791101.57.791215.58ε, Вt, с
ε

Calculated result

Φ
0.02 Вб
ε
0 В
εмакс
12.57 В
Explaining the result

Emf depends on the rate of flux change. When |Φ| is largest, ε = 0; at Φ = 0, |ε| is largest. Doubling ν doubles the emf amplitude.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.