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GRADE 9 · NUCLEAR PHYSICS

Binding energy, fission and reactor

Mass defect, chain reactions, critical conditions and nuclear power.

32 minutes6 theory cards
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Understanding step by step

A bound nucleus has less mass than the sum of the masses of the same protons and neutrons separately. No nucleon has vanished. Our comparison of the two states must therefore also account for interaction energy.

Compare masses of the same particlesFree: 2p + 2n⁴He nucleus: 2p + 2n+00++00+2mₚ + 2mₙ>mядраThe same four nucleonsThe difference is related to energyNucleons do not disappear
The same two protons and two neutrons are compared: free particles on the left, a bound helium-4 nucleus on the right. Plus indicates proton charge and zero neutron neutrality. Composition is unchanged, but the bound state has less mass than the sum of free particle masses. Sizes and distances are schematic; no missing nucleon represents the mass difference.

Energy is needed to break the binding

Separating a bound nucleus into free protons and neutrons requires an energy input: particles do not simply fly apart from a stable bound system. The required amount is called binding energy Eсв. Forming the same nucleus from free nucleons can release the corresponding energy. We compare the same particles in two states; a more strongly bound system needs more energy for complete separation.

Separation and reverse formation+00++00+Supply Eсв+00++00+Release EсвSame 2p + 2n in each state
In the upper row, a helium-4 nucleus is separated into two free protons and two neutrons: binding energy is supplied. In the lower row, the same free particles form a nucleus and the corresponding energy is released. Particle counts and charges are conserved in both rows. Arrows between states indicate the process; vertical arrows indicate energy transfer. Sizes are schematic.

Mass of the bound state

Define Δm = sum of free nucleon masses − nuclear mass. This mass defect is positive for a nucleus bound relative to those separated particles. Nucleons do not disappear: the bound system's total rest energy decreases, and so does its mass. Imagine separating the particles and supplying the necessary energy: the separated system then has more mass. 'Defect' describes a comparison, not damaged matter.

Δm = mass sum − nuclear massmass sum−nuclear massΔm > 0no nucleons have vanishedless mass — less system energy
Mass defect is the sum of free nucleon masses minus nuclear mass. It is positive for a bound nucleus, but no nucleons disappear.

Convert mass difference to energy

The relation is Eсв = Δmc², where c is the vacuum speed of light. Doubling Δm doubles binding energy. To obtain joules, use kilograms for Δm and m/s for c; кг·м²/с² does give Дж. The very large c² explains why a small mass difference corresponds to appreciable energy. At Δm = 0, binding energy relative to the chosen free particles would be zero.

Mass difference corresponds to energyFree: 2p + 2n⁴He nucleus: 2p + 2n+00++00+2mₚ + 2mₙ>mядраThe same four nucleonsEсв = Δm·c²кг · (м/с)² = Дж
On the left are two free protons and two neutrons; on the right is a helium-4 nucleus made of those same particles. Plus signs mark protons and zeros mark neutrons. Nuclear mass is below 2mₚ+2mₙ by the positive mass defect Δm. Binding energy Eсв=Δmc² is needed for separation; the reverse formation releases the corresponding energy. Particle sizes are schematic. For joules, use mass in kilograms and speed in m/s.

A small mass unit

Individual nuclear masses are inconveniently small in kilograms. The atomic mass unit equals one twelfth of the mass of a free carbon-12 atom at rest in its ground state, approximately 1.66·10⁻²⁷ kg. It is a mass unit, not the nucleon count A. When comparing tabulated atomic and nuclear masses, remember electron masses: calculating a mass defect requires a consistent set of objects to compare.

A fraction of the whole atom's mass¹²C atomic mass = 12 а.е.м.1/12 of atomic mass = 1 а.е.м.1 а.е.м. ≈ 1,66·10⁻²⁷ кгFree atom at restand in its ground state
The bar represents the mass of a whole free carbon-12 atom at rest in its ground state, including electrons. It is divided into twelve equal mass fractions; one highlighted fraction is one atomic mass unit. This is not a cross-section of the atom or twelve separate nucleons. One atomic mass unit is approximately 1.66·10⁻²⁷ kg.

A small energy unit

Small energies also benefit from a convenient unit. An electronvolt, eV, is the energy gained by an electron accelerated in vacuum through a potential difference of 1 V, about 1.6·10⁻¹⁹ J. MeV means one million electronvolts. The particle merely helps define the unit: nuclear and photon energies can also be given in electronvolts. A volt and an electronvolt are not interchangeable: the former measures voltage, the latter energy.

Potential difference: 1 В−+Field E−Motion and force on e⁻Gain in Eкин = 1 эВ1 эВ ≈ 1,6·10⁻¹⁹ Дж1 МэВ = 10⁶ эВ
In vacuum, an electron moves from the negative plate towards the positive plate. The electric field points left; the force on the negative electron points right. Across a potential difference of 1 V, its kinetic energy increases by 1 eV. This is an energy gain, not necessarily its entire final energy. An electronvolt is an energy unit; 1 МэВ = 10⁶ эВ.

Convenient nuclear units

To avoid converting mass to kilograms each time, use 1 а.е.м.·c² ≈ 931,5 МэВ. Multiply Δm in atomic mass units by 931.5 to obtain energy in MeV. This is still Eсв = Δmc², using different units. You cannot insert a mass in atomic mass units alongside c in m/s and call the result joules: units must remain consistent throughout.

Nuclear unitsmass in а.е.м.energy in эВ1 а.е.м. · c² ≈ 931,5 МэВDo not mix а.е.м.with kg without conversion
Nuclear calculations use atomic mass units for mass and electronvolts for energy, linked by a conversion factor. Do not mix atomic mass units with kilograms.

Compare binding per nucleon

A large nucleus usually has greater total binding energy simply because it contains more particles. To compare average binding, divide Eсв by A. In energy-releasing fission, the final particles have a smaller total mass, and the difference appears as kinetic energy and radiation. Average binding energy alone, however, cannot predict radioactive stability: the specific available transformations and their energy conditions matter.

Eсв / A — mean binding per nucleonHeavy nucleusFragmentsStronger binding → less massQualitative scale
This schematically compares energy-releasing fission of a heavy nucleus. Bars show binding energy per nucleon: fragments are more strongly bound on average. The scale is qualitative; heights do not specify a measured ratio. Exact energy yield requires comparing all initial particle masses, including the incoming neutron, with all products, including free neutrons. The difference is released as kinetic energy and radiation; average binding alone does not determine radioactive stability.

What happens in fission

Some heavy nuclei, such as uranium-235, can absorb a neutron and split into lighter fragments, emitting new neutrons and releasing energy. This is fission, not the emission of a single alpha or beta particle. Energy is released because the final particles have a smaller total mass. Breaking just any nucleus is not guaranteed to release energy: the direction of the energy balance must be checked.

U-235 fission releases energyn²³⁵UZ = 92Products¹⁴¹Ba⁹²Kr3n235 + 1 = 141 + 92 + 392 = 56 + 36One possible channel
One possible channel: a uranium-235 nucleus absorbs a neutron and produces barium-141, krypton-92 and three neutrons, releasing energy. Mass numbers balance: 235+1=141+92+3; atomic numbers: 92=56+36. Named circles symbolize whole nuclei, not drawn nucleons or their actual sizes. Other fissions can have different products. Moving particles and radiation carry the energy away.

Will the chain continue?

Neutrons from one fission can cause further fissions. If each event leads on average to one next event, the chain is sustained; fewer than one makes it die out. Not every neutron continues the chain: some leave the material or are absorbed without the required fission. The balance matters, not merely the number of neutrons produced. This qualitative model explains self-sustaining behaviour without assuming every neutron must find another nucleus.

Not every neutron continues the chainfissionfissionfissionabsorptionleakageneutronOne next event on average sustains the chain
Each circle is a fission event; blue arrows show some paths of emitted neutrons. A neutron may cause another fission, be absorbed without fission or leave the material. Three consecutive events and examples of losses are shown; line counts do not specify the exact neutron yield per event. A self-sustaining chain depends on average balance: one next fission per previous fission on average. Material size, shape and composition are not specified here.

Critical conditions

A state is critical when neutron production and losses sustain the chain. Critical mass is therefore not a universal number for any piece of material: composition, geometry and absorption also matter. Changing the surroundings changes neutron losses even at the same mass. The point is to understand how conditions depend on one another, rather than reduce a chain reaction to 'lots of material'.

Mean subsequent fissionsBelow 1012Dies outEqual to 1012SustainedAbove 1012Grows0, 1, 2: generations; schematic heightsNo universal critical mass
Three schematic charts show the mean fission count in successive generations. If the average number of subsequent fissions is below one, it falls; at one it stays constant; above one it grows. These are statistical trends, not predetermined branches for each event. Criticality is the balance of neutron production and losses. No universal critical mass is specified: composition, shape and surroundings also matter.

Controlling a reactor

A reactor controls the number of neutrons able to continue the chain. Control rods absorb some neutrons, while coolant removes the released heat. In thermal reactors, a moderator slows neutrons, a different function from absorption. One material may serve several functions, but the physical roles must be distinguished. Chain control and cooling are linked in operation, yet neither replaces the other.

Three distinct functionsControl rodsModeratorCoolantv₁v₂ < v₁Absorb nReduce speedCarry heat awaySlowing is not absorptionThermal-reactor functions
Three separate diagrams distinguish thermal-reactor functions. A rod absorbs a neutron: the path ends at the absorber. In the moderator, a neutron continues more slowly after a collision, giving some energy to matter; arrow lengths compare speeds only qualitatively. Coolant carries heat away from fuel. These are distinct roles, although one material can perform two in some reactors. The diagrams do not depict a specific reactor design.

From nuclei to electricity

Fission energy first becomes mainly kinetic energy of the products, then heats the material and coolant. A thermal cycle drives a turbine and a generator produces electricity. Even after the main chain stops, fission products continue to decay radioactively and release residual heat. Stopping the chain therefore does not stop heating instantly: cooling, shielding and radioactive-material management remain necessary.

Energy flow in a nuclear power stationFissionand heatCoolantand thermal cycleTurbineGeneratorElectricalenergyCold reservoirHeat rejectedCooling continues after the chain stops
Fission energy passes to coolant and a thermal cycle converts it into turbine work. The turbine turns a generator to produce electrical energy. A thermal cycle must reject some energy to a cold reservoir. This shows energy transfer, not a particular plant's pipework. After the chain stops, fission products still release heat, so cooling continues; shielding and radioactive-material management are also needed.

Binding energy from mass defect

A nucleus has a mass defect of 0.01 atomic mass units. Find its binding energy using 1 а.е.м.·c² = 931,5 МэВ.

Δm = 0,01 а.е.м.EFree nucleonsBound nucleusEсвBinding energy — ?Find the energy difference1 а.е.м.·c² = 931,5 МэВ
The diagram compares the rest energy of the bound nucleus with that of the same free nucleons. The lower level is the nucleus, the upper one the separated particles. Mass defect is 0.01 atomic mass units; find binding energy. Level spacing is schematic; absolute energies and the unknown nucleus's composition are unspecified. This scale is retained in later steps.

Let's look at an example · 1

Mass defect compares separated nucleons with the bound nucleus. Separating the nucleus requires an input Eсв = Δmc².

Δm = 0,01 а.е.м.EFree nucleonsBound nucleusEсвInputEсв = Δm·c²1 а.е.м.·c² = 931,5 МэВ
The same energy scale and mass defect are shown. The added upward arrow means supplying energy to separate the nucleus into the same free nucleons. The required difference Eсв equals Δmc². The given factor links one atomic mass unit, multiplied by c², to 931.5 MeV.

Let's look at an example · 2

The given equivalence already converts а.е.м.·c² to МэВ: Eсв = 0,01 · 931,5 = 9,315 МэВ.

Δm = 0,01 а.е.м.EFree nucleonsBound nucleusEсвInput0,01 · 931,5 = 9,315 МэВа.е.м. · (МэВ / а.е.м.) = МэВ
The levels, spacing, input arrow and mass defect are unchanged. Multiply 0.01 atomic mass units by 931.5 MeV per atomic mass unit to obtain 9.315 MeV. Atomic mass units cancel; kilograms and joules are not mixed into this calculation route. The result describes the same difference between the levels.

Let's look at an example · 3

The positive result means energy must be supplied for separation. In the reverse binding of the same free nucleons, it corresponds to a decrease in the system's rest energy.

Δm = 0,01 а.е.м.EFree nucleonsBound nucleusEсвInputEсв = 9,315 МэВ > 0Rest energy is greater after separation
The same scale explains the positive answer of 9.315 MeV. Energy must be supplied for separation: the free nucleons' total rest energy exceeds that of the bound nucleus. The particle composition is unchanged in this comparison. This is not energy gained by taking the nucleus apart, nor a claim about an unspecified isotope.

Check the result

The binding energy is 9.315 MeV. This corresponds to the stated mass defect and is required to separate the nucleus into free nucleons.

Key point · 1

A system's mass depends on its energy state: binding reduces rest energy without losing nucleons.

Key point · 2

Eсв = Δmc² relates a measurable mass difference to energy; the chosen units must be consistent.

Key point · 3

Fission can release energy and sustain a chain, while neutron control and heat removal serve different purposes.

What comes next

Next, compare fission with fusion and examine how radiation interacts with matter.

Basic Concepts

3 concepts

Fission and chain reaction

A heavy nucleus can split, releasing energy and neutrons that can cause new fissions.

A self-sustaining chain requires critical conditions; critical mass depends not just on the amount of material, but also on shape, composition and neutron losses.

Mass defect and binding energy

A bound nucleus has less mass than the sum of free nucleon masses; the difference corresponds to binding energy.

Binding energy per nucleon describes average binding strength. In an energy-releasing reaction, the total final particle mass is less than the initial mass; stability against radioactive decay cannot be determined from average binding energy alone.

Nuclear reactor

The device maintains a controlled chain reaction and removes heat for subsequent generation of electricity.

Nuclear power provides a lot of energy with low direct carbon emissions, but requires strict safety, waste management and accident prevention.

Physical quantities

2 quantities

Mass defect

\Delta m

The sum of free nucleon masses minus the mass of the bound nucleus.

Unit: atomic mass unit · \mathrm{а.е.м.}

Binding energy

E_{\text{св}}

The energy needed to separate a nucleus into free nucleons.

Unit: joule · \mathrm{Дж}

Lesson formulas

1 formula

Binding energy

E_{\text{св}}=\Delta mc^2

Binding energy equals mass defect multiplied by the square of the speed of light.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.