GRADE 8 PRACTICE
Physics Problems: Conductor connections, Grade 8
Series, parallel and mixed circuits.
Here the conditions and analysis of the solution can be read without an account. In the simulator, you need to collect the same analyzes yourself: “Given,” formulas, order of steps and answer.
Problem statements
The answer options are there to check against, and the walkthrough opens under each problem.
Problem #49
Series connectionWhat concept does the description correspond to: “The elements are connected one after the other without branching, so the same current passes through them.»?
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- \text{Description}
- \text{The elements are connected one after the other without branching, so the same current passes through them.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
The total voltage is distributed between the elements, and the equivalent resistance is equal to the sum of the resistances.
- \text{Let's formulate conclusion}\text{Concept} = \text{Series connection}
Answer\text{Concept} = \text{Series connection}
Problem #50
Series connectionWhat concept does the description correspond to: “The ammeter shows the same current in different places, and the sum of the voltages across the elements is equal to the source voltage.»?
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- \text{Description}
- \text{The ammeter shows the same current in different places, and the sum of the voltages across the elements is equal to the source voltage.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
Checking these relationships helps detect assembly errors and confirm connection rules.
- \text{Let's formulate conclusion}\text{Concept} = \text{Series circuit measurement}
Answer\text{Concept} = \text{Series circuit measurement}
Problem #51
Conductor connections4 ohm and 6 ohm resistors are connected in series and connected to 12 V. Find the total resistance and current.
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- R_1
- 4\,\text{Ом}
- R_2
- 6\,\text{Ом}
- U
- 12\,\text{В}
R - ?I - ?
- R=R_1+R_2R=4+6\,\text{Ом}R = 10\,\text{Ом}
- I=\frac{U}{R}I=\frac{12}{10}\,\text{А}I = 1{,}2\,\text{А}
Answer10\,\text{Ом}1{,}2\,\text{А}
Problem #52
Parallel and mixed connectionWhat concept does the description correspond to: “The elements are connected to one pair of nodes, so the voltage on each branch is the same.»?
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- \text{Description}
- \text{The elements are connected to one pair of nodes, so the voltage on each branch is the same.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
The total current is equal to the sum of the branch currents, and adding a new branch reduces the equivalent resistance.
- \text{Let's formulate conclusion}\text{Concept} = \text{Parallel connection}
Answer\text{Concept} = \text{Parallel connection}
Problem #53
Parallel and mixed connectionWhat concept does the description correspond to: “One resistance that, at the same voltage, draws the same total current as the entire combination.»?
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- \text{Description}
- \text{One resistance that, at the same voltage, draws the same total current as the entire combination.}
\text{name concepts} - ?
- \text{Let's compare approval with definition}
For parallel branches, the equivalent resistance is less than any individual resistance.
- \text{Let's formulate conclusion}\text{Concept} = \text{Equivalent resistance}
Answer\text{Concept} = \text{Equivalent resistance}
Problem #54
Conductor connections6 ohm and 3 ohm resistors are connected in parallel at 12 V. Find the equivalent resistance and the total current.
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- R_1
- 6\,\text{Ом}
- R_2
- 3\,\text{Ом}
- U
- 12\,\text{В}
R - ?I - ?
- R=\frac{R_1R_2}{R_1+R_2}R=\frac{6\cdot3}{6+3}\,\text{Ом}R = 2\,\text{Ом}
- I=\frac{U}{R}I=\frac{12}{2}\,\text{А}I = 6\,\text{А}
Answer2\,\text{Ом}6\,\text{А}
Problem #169
Series connectionresistors 4 and 8 Ohm connected sequentially. Find Total resistance.
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- R_1
- 4\,\text{Ом}
- R_2
- 8\,\text{Ом}
R - ?
- R=R_1+R_2R=4 + 8R=12\,\text{Ом}
In a series circuit, the resistances add up.
Answer12\,\text{Ом}
Problem #170
Series connectionresistors 6 and 9 Ohm connected sequentially. Find Total resistance.
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- R_1
- 6\,\text{Ом}
- R_2
- 9\,\text{Ом}
R - ?
- R=R_1+R_2R=6 + 9R=15\,\text{Ом}
In a series circuit, the resistances add up.
Answer15\,\text{Ом}
Problem #171
Series connectionConsistently connected resistors 3 and 5 Ohm connected to voltage 16 B. Find current.
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- R_1
- 3\,\text{Ом}
- R_2
- 5\,\text{Ом}
- U
- 16\,\text{В}
I - ?
- R=R_1+R_2R=3 + 5R=8\,\text{Ом}
We find the total resistance.
- I=\frac{U}{R}I=\frac{16}{8}I=2\,\text{А}
The same current passes through both resistors.
Answer2\,\text{А}
Problem #172
Series connectionConsistently connected resistors 5 and 7 Ohm connected to voltage 36 B. Find current.
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- R_1
- 5\,\text{Ом}
- R_2
- 7\,\text{Ом}
- U
- 36\,\text{В}
I - ?
- R=R_1+R_2R=5 + 7R=12\,\text{Ом}
We find the total resistance.
- I=\frac{U}{R}I=\frac{36}{12}I=3\,\text{А}
The same current passes through both resistors.
Answer3\,\text{А}
Problem #173
Series connectionTwo resistor 4 and 8 Ohm connected sequentially with source 18 B. Find Voltage across the second resistor.
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- R_1
- 4\,\text{Ом}
- R_2
- 8\,\text{Ом}
- U
- 18\,\text{В}
U_2 - ?
- R=R_1+R_2R=4 + 8R=12\,\text{Ом}
Add up the resistances.
- I=\frac{U}{R}I=\frac{18}{12}I=1{,}5\,\text{А}
Find the total current.
- U_2=IR_2U_2=1{,}5 \cdot 8U_2=12\,\text{В}
Voltages are distributed proportionally to resistances.
Answer12\,\text{В}
Problem #174
Series connectionTwo resistor 5 and 15 Ohm connected sequentially with source 24 B. Find Voltage across the second resistor.
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- R_1
- 5\,\text{Ом}
- R_2
- 15\,\text{Ом}
- U
- 24\,\text{В}
U_2 - ?
- R=R_1+R_2R=5 + 15R=20\,\text{Ом}
Add up the resistances.
- I=\frac{U}{R}I=\frac{24}{20}I=1{,}2\,\text{А}
Find the total current.
- U_2=IR_2U_2=1{,}2 \cdot 15U_2=18\,\text{В}
Voltages are distributed proportionally to resistances.
Answer18\,\text{В}
Problem #175
Parallel and mixed connectionCurrents flow in two parallel branches 2 and 3 A. Find the current in the unbranched part.
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- I_1
- 2\,\text{А}
- I_2
- 3\,\text{А}
I - ?
- I=I_1+I_2I=2 + 3I=5\,\text{А}
Charge does not accumulate in the circuit node.
Answer5\,\text{А}
Problem #176
Parallel and mixed connectionCurrents flow in two parallel branches 3 and 5 A. Find the current in the unbranched part.
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- I_1
- 3\,\text{А}
- I_2
- 5\,\text{А}
I - ?
- I=I_1+I_2I=3 + 5I=8\,\text{А}
Charge does not accumulate in the circuit node.
Answer8\,\text{А}
Problem #177
Parallel and mixed connectionresistors 6 and 3 Ohms connected in parallel at voltage 12 B. Find the total current.
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- R_1
- 6\,\text{Ом}
- R_2
- 3\,\text{Ом}
- U
- 12\,\text{В}
I - ?
- I_1=\frac{U}{R_1}I_1=\frac{12}{6}I_1=2\,\text{А}
Both branches have the same voltage.
- I_2=\frac{U}{R_2}I_2=\frac{12}{3}I_2=4\,\text{А}
Separately, we find the current of the second branch.
- I=I_1+I_2I=2 + 4I=6\,\text{А}
We add up the branch currents.
Answer6\,\text{А}
Problem #178
Parallel and mixed connectionresistors 8 and 4 Ohms connected in parallel at voltage 24 B. Find the total current.
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- R_1
- 8\,\text{Ом}
- R_2
- 4\,\text{Ом}
- U
- 24\,\text{В}
I - ?
- I_1=\frac{U}{R_1}I_1=\frac{24}{8}I_1=3\,\text{А}
Both branches have the same voltage.
- I_2=\frac{U}{R_2}I_2=\frac{24}{4}I_2=6\,\text{А}
Separately, we find the current of the second branch.
- I=I_1+I_2I=3 + 6I=9\,\text{А}
We add up the branch currents.
Answer9\,\text{А}
Problem #179
Parallel and mixed connectionresistors 6 and 3 Ohms connected in parallel; there is a resistor in series with this pair 4 Ohm. Whole circuit voltage 18 B. Find the voltage across the parallel pair.
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- R_1
- 6\,\text{Ом}
- R_2
- 3\,\text{Ом}
- R_3
- 4\,\text{Ом}
- U
- 18\,\text{В}
V - ?
- R=\frac{R_1R_2}{R_1+R_2}R=\frac{6 \cdot 3}{(6 + 3)}R=2\,\text{Ом}
We replace the parallel pair with an equivalent resistance.
- I=\frac{U}{R+R_3}I=\frac{18}{(2 + 4)}I=3\,\text{А}
We find the current in the entire circuit.
- V=IRV=3 \cdot 2V=6\,\text{В}
The voltage across the pair is equal to the current of the common circuit multiplied by its resistance.
Answer6\,\text{В}
Problem #180
Parallel and mixed connectionresistors 12 and 6 Ohms connected in parallel; there is a resistor in series with this pair 2 Ohm. Whole circuit voltage 24 B. Find the voltage across the parallel pair.
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- R_1
- 12\,\text{Ом}
- R_2
- 6\,\text{Ом}
- R_3
- 2\,\text{Ом}
- U
- 24\,\text{В}
V - ?
- R=\frac{R_1R_2}{R_1+R_2}R=\frac{12 \cdot 6}{(12 + 6)}R=4\,\text{Ом}
We replace the parallel pair with an equivalent resistance.
- I=\frac{U}{R+R_3}I=\frac{24}{(4 + 2)}I=4\,\text{А}
We find the current in the entire circuit.
- V=IRV=4 \cdot 4V=16\,\text{В}
The voltage across the pair is equal to the current of the common circuit multiplied by its resistance.
Answer16\,\text{В}
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