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GRADE 7 · MASS AND DENSITY

Volume and density

Define density and use it to calculate mass or volume.

22 minutes8 theory cards
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Understanding step by step

A small metal part can be heavier than a large wooden one. Are we comparing size or material? To separate these effects, we will first learn to measure volume, then compare the masses of equal volumes.

Cubes of the same sizealuminiumironvolumes are equalSame size but different mass — why?
Place two equally sized cubes on a balance: the iron cube has more mass than the aluminium cube. To compare the materials rather than the samples, compare the masses of equal volumes.

How much space does an object occupy?

How many identical small cubes fit inside a rectangular block? Its length and width determine the number in one layer; its height determines how many layers fit. This gives volume V, a measure of occupied space: V = abc, where a, b, c are the three dimensions. Double only the height and volume doubles. Double every dimension and volume becomes eight times as large. If dimensions are in metres, the product is in m³, cubic metres.

Multiply the three dimensions2 см5 см4 смV = 5 · 4 · 2 = 40 см³
Length, width and height are multiplied. If all dimensions are expressed in centimeters, the volume is obtained in cubic centimeters.

An irregularly shaped object

A stone has no three dimensions whose product gives its exact volume. But we can let water ‘measure’ its shape. A fully submerged object occupies space previously filled by water, so the graduated cylinder reading rises by the object's volume. Subtract the initial reading from the final reading. The object must not dissolve or absorb water, and no bubbles should cling to it. Open cavities that fill with water are not included in the displaced volume measured this way.

40 мл70 млV = 30 см³
The graduated cylinder reads 40 ml before immersion and 70 ml after the object is fully submerged. Its volume is 70 − 40 = 30 мл = 30 см³.

Converting volume units

Why is multiplying by 100 not enough when converting cubic metres? Imagine cutting a cube of side 1 m into centimetre cubes. There are 100 along each of the three directions, giving 100·100·100 = 1 000 000 in total. Hence 1 м³ = 1 000 000 см³. One millilitre equals 1 cm³, and 1 л = 1000 см³ = 0,001 м³. A cubic unit includes all three dimensions. Sketching the cube is a useful check on a conversion.

One hundred centimetres along each edge1 м1 м1 м100 × 100 × 100= 1 000 000 см³this is 1 м³1 л = 1000 см³= 0,001 м³
Each edge of a one-cubic-metre cube is one hundred centimetres long, so the cube contains one million cubic centimetres. A litre equals one thousand cubic centimetres.

Masses of equal volumes

Take aluminium and iron cubes with equal volumes. Their different masses can no longer be explained by size: the material differs. The mass per unit volume of a uniform substance is its density ρ. A greater mass in the same volume means a greater density. The SI unit is kg/m³: the value tells us the mass of one cubic metre. We can also use g/cm³, provided mass and volume are expressed in compatible units.

AluminiumIron1 см³1 см³≈ 2,7 г≈ 7,9 гρ = m / V
Both samples have a volume of 1 cm³. At room temperature, their masses are approximately 2.7 g for aluminium and 7.9 g for iron. Density compares mass at equal volume.

From a sample to a substance

We do not need a whole cubic metre of material. Equal volumes within a uniform sample have equal masses, so divide the mass of any sample by its volume: ρ = m/V. Cut it in half: both mass and volume halve, leaving the ratio unchanged. Density describes the substance, whereas mass describes the particular object. But compress the same mass into a smaller volume and its density rises. Constancy assumes unchanged conditions and state of matter.

Cut the block in halfm = 40 гV = 20 см³20 г20 г10 см³10 см³ρ = 40 : 20 = 20 : 10 = 2 г/см³density has not changed
Half of a homogeneous block has half the mass and volume, but their ratio has not changed. Under the same conditions, the density of the substance does not depend on the size of such a sample.

Compare with a density table

We measure a density and find a similar value in a table. Does that identify the material for certain? No: different materials can have similar densities, and a cavity lowers an object's average density. Table values refer to particular temperatures and states of matter. First match the units and conditions, then use the agreement as evidence for a possible material. Ice and liquid water have different densities even though they are the same substance.

Rounded values at 20 °Cwater — 1000aluminium — 2700iron — 7900кг/м³measured2700 кг/м³A match suggests the material,but does not prove the composition
An example table for ordinary room conditions, with rounded values. Convert the measured density to the table's units. Agreement suggests a material but does not by itself prove the sample's composition.

Find mass from density

If each cubic metre has a mass of ρ kilograms, what mass is contained in V cubic metres? Adding equal portions gives m = ρV. At the same density, doubling volume doubles mass; half the volume has half the mass. The units agree too: (кг/м³)·м³ = кг. For a composite or hollow object, use its average density or calculate the masses of the parts separately.

Mass of one and two cubic meters of water1 м³1000 кг2 м³2000 кгm = ρ · V = 1000 · 2 = 2000 кг
With water's density approximately one thousand kilograms per cubic metre, one cubic metre has a mass of about one thousand kilograms. Twice that volume has twice the mass: m = ρV.

Find volume from mass

We now know the mass to be accommodated and the mass per cubic metre. The required volume is V = m/ρ. For the same mass, a denser substance occupies less volume because each cubic metre holds more mass. For a hollow or composite object, total mass divided by external volume gives average density. This describes the whole chosen object, including its cavities, and need not equal the density of its wall material.

Divide mass by density5,4 кгaluminium: ρvolume of metal0,002 м³this is 2 litresV = m : ρ = 5,4 : 2700
Aluminium of mass 5.4 kilograms and density 2700 kilograms per cubic metre occupies 0.002 cubic metres. For a hollow object, dividing mass by the material's density gives the volume of material only, excluding the cavities.

Volume from a graduated cylinder

A graduated cylinder reads 40 ml before an insoluble part is fully submerged, and 70 ml afterwards. The part does not absorb water and has no bubbles attached; its mass is 81 g. Find its average density.

What was measured?40 мл70 млbeforeafter81 гthe same partAverage density — ?
The graduated cylinder reads 40 ml before immersion and 70 ml after the part is fully submerged. The same part has a mass of 81 g. It neither dissolves nor absorbs water, and has no bubbles attached. Find its average density.

Let's look at an example · 1

The part's volume is the difference between readings: 70 − 40 = 30 мл = 30 см³.

Difference between water readings40 мл70 млbeforeafter81 гthe same partV = 70 − 40 = 30 мл = 30 см³
The graduated cylinder reads forty millilitres before immersion and seventy afterwards. The part displaces thirty millilitres of water, which is also its volume in cubic centimetres.

Let's look at an example · 2

Density is mass divided by volume: 81/30 = 2,7 г/см³.

Calculate density40 мл70 млbeforeafter81 гthe same partρ = 81 г : 30 см³ = 2,7 г/см³
Eighty-one grams occupy thirty cubic centimetres. Their ratio gives a density of two point seven grams per cubic centimetre.

Let's look at an example · 3

In SI units this is 2700 kg/m³: 1 г/см³ = 1000 кг/м³. To identify the material, we must also know that the part is uniform and has no cavities.

Convert to kilograms per cubic metre2,7 г/см³× 10002700 кг/м³1 г/см³ = 1000 кг/м³The density matches aluminium,but uniformity and absence of cavitiesstill need to be checked
One gram per cubic centimetre equals one thousand kilograms per cubic metre, so the result is two thousand seven hundred. Density alone has not yet established the material.

Let's check the result

Average density: 2,7 г/см³ = 2700 кг/м³.

Key idea · 1

Density lets us compare substances independently of the size of a uniform sample: cutting it leaves m/V unchanged.

Key idea · 2

The formulas ρ = m/V, m = ρV and V = m/ρ answer different questions about the same relationship between mass and volume.

Key idea · 3

Displacement measurements and comparisons with tables require the stated conditions; average density matters for hollow objects.

Where do we go next?

Mass also affects Earth's gravitational pull on an object. Next we will distinguish mass, gravitational force and apparent weight.

Basic Concepts

3 concepts

Volume

A physical quantity that measures the space occupied by an object or substance.

Find a rectangular block's volume from its dimensions and an irregular object's volume from the liquid it displaces.

Density table

A reference table lists substances and their densities at specified temperatures and states of matter.

Before using the table, express mass and volume in compatible units and check the substance's state of matter.

Density

A physical quantity equal to the mass of a unit volume of a homogeneous substance.

Aluminium and steel objects with equal volumes have different masses because the materials have different densities.

Physical quantities

2 quantities

Volume

V

The object's volume used to calculate density.

Unit: cubic metre · \mathrm{м}^3

Density

\rho

The mass of a homogeneous substance per unit volume.

Unit: kilogram per cubic metre · \frac{\mathrm{кг}}{\mathrm{м}^3}

Lesson formulas

3 formulas

Density of a substance

\rho = \frac{m}{V}

Density is equal to the mass of a homogeneous body divided by its volume.

Mass from density

m = \rho V

Find mass by multiplying the substance's density by the object's volume.

Volume from density

V = \frac{m}{\rho}

Find volume by dividing the object's mass by the density of its material.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.