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GRADE 7 · WORK, POWER AND ENERGY

Levers and pulleys

Moment arm, torque, lever equilibrium and the golden rule of mechanics.

24 minutes7 theory cards
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Read the full lesson theory here without an account. In the interactive lesson, the same theory is presented as cards, followed by questions with feedback and practice problems. Your progress is saved.

Understanding step by step

Try opening a door by pushing near its hinges, then near its handle. The same force has different effects. What gives the advantage: door length, where you push, or the push's direction?

Door from abovelarger torquesmaller torquehinges on the leftsame force, different position
Top view: the same force acts perpendicular to the door. Farther from the hinges, its moment arm and torque are greater; nearer, they are smaller. This compares turning effects, not a claim that a door cannot turn when pushed near the hinges.

Lever and pivot

A seesaw can balance a heavy person on a short arm against a light person on a long arm. Comparing forces alone is not enough: their ability to turn the board about the pivot matters. A rigid object that can turn about a support is called a lever. One force may tend to turn it clockwise, another anticlockwise. First identify the axis and possible turning directions, then compare their effects.

Two forces, opposite turnsF₁F₂anticlockwiseclockwiseSupport: the pivotForce alone is not enough
Forces on opposite sides of the support tend to turn the lever in opposite directions. Force magnitude alone cannot tell us which effect will prevail.

Find the line of action

Extend a force arrow in both directions to obtain its line of action. Draw a perpendicular from the axis to that line: its length l is the moment arm. Why this distance? A push along the door towards its hinges barely turns it, even with your hand far from the axis: the line of action passes through the axis and the moment arm is zero. Distance to the application point equals the moment arm only for the appropriate force direction, not always.

Moment arm: perpendicular to force line2 м1 м2 Н4 Н2 · 2 = 4 · 1 = 4 Н·м
The lever is inclined, while the forces are vertical. Moment arms are horizontal distances from the axis to the dashed lines of action, not the sloping lever sections. 2 Н · 2 м = 4 Н · 1 м, so the torques are equal. Neglect lever weight; force arrows and moment arms use consistent scales.

Measuring the turning effect

The turning effect increases with both force and moment arm. Its measure is the torque magnitude M = Fl. Doubling one factor while keeping the other fixed doubles torque; a line through the axis gives l = 0 and zero torque. Force in N times arm in m gives N·m. Torque and work have the same dimensions but different meanings: no displacement is specified here, so the torque unit is called a newton-metre, not a joule.

M = F · lF = 4 Нl = 0,5 мM = 4 · 0,5 = 2 Н·мН·м is not called a joule here
Torque equals force multiplied by moment arm: newtons times metres give newton-metres. We do not call this unit a joule here: torque describes a turning effect, not transferred energy.

Condition for equilibrium

For a stationary lever not to start rotating, opposite turning effects must balance. For two such forces, F₁l₁ = F₂l₂. Twice the moment arm requires only half the force: the products stay equal. Include every torque, including the lever's gravity; ignore it only if instructed, or if its line of action passes through the axis and its torque is zero. The formula describes rotational equilibrium about a fixed axis.

F₁ · l₁ = F₂ · l₂0,6 м0,2 м2 Н6 Н2 · 0,6 = 6 · 0,2 = 1,2 Н·мNeglect lever weight
Neglect lever weight. Arms of 0.6 and 0.2 m have ratio 3 to 1; forces of 2 and 6 N have ratio 1 to 3. Both torques are 1.2 N·m and act oppositely. Lines of action extend to the arm brackets.

Fixed pulley

Pass a rope over a wheel with a fixed axle: pull down and the load rises. This is a fixed pulley. In the ideal model, a massless inextensible rope with no friction has equal tension on both sides. During slow lifting, the pull therefore equals the load's gravitational force: there is no force gain. The pulley makes pulling more convenient by changing its direction. Each metre the load rises requires a metre of movement of the free end.

LoadPull
The pulley's axis is fixed. Pull the free end down and the load rises the same distance. At rest or during uniform lifting, tension equals the load's gravitational force; an ideal fixed pulley gives no force gain. The rope is massless and friction is neglected.

Movable pulley

Now attach the load to a pulley that can move, supported by two vertical rope strands. Each ideal strand has the same tension T, giving 2T together. For slow lifting and negligible pulley weight, 2T = mg, so the free-end pull is T = mg/2. The movable pulley thus gives a twofold force gain. Inclined strands or a heavy pulley require us to revise this equation.

Two strands support the load20 Н10 Н10 НF = 10 Нpull upwardsTwo forces of 10 Н give 20 Н
The left end is fixed; the free right end is pulled upwards. The rope passes under the pulley, and two vertical strands support the load. At rest or during uniform lifting, the shown 20 N load is shared by two tensions of 10 N each. Neglect pulley and rope weights and friction.

Why work does not decrease

Have we obtained work for free? Raise a movable pulley by 1 m: each supporting strand shortens by 1 m. The free end must therefore take up 2 m of rope. Half the force over twice the distance leaves Fs unchanged. This is the golden rule of mechanics: an ideal simple machine trades force for distance without reducing work. Tracking rope length reveals the reason, not just the rule.

Before liftingAfter1 м2 мThe end moves twice as far as the load
The upper fixed pulley only changes pull direction. The same pulleys and load are shown before and after lifting. The load rises 1 m, each supporting strand shortens 1 m, and the free end moves 2 m down. Displacements share one scale; rope length is conserved.

A real machine

A real pulley has axle friction, bending rope and deforming parts. The same lift therefore requires more input work than in the ideal model. A smaller effort may still make a task possible, but it does not mean lower total energy expenditure. The ideal model gives a clear limit: it shows the maximum force gain and helps us account separately for extra energy needed by a real device.

IdealRealinputall usefulinputusefulfrictionThe machine creates no energy
An ideal machine gives no reduction in work; a real one also needs work against friction and deformation. Reducing effort does not create energy.

Lever equilibrium

A force of 50 N acts with a moment arm of 0.4 m. Find the force producing the opposite torque with a moment arm of 0.1 m. Neglect the lever's weight.

Neglect lever weightl₁ = 0,4 мl₂ = 0,1 м50 НF₂ — ?What force balances the lever?
A force of 50 N acts with a 0.4 m moment arm. An opposing torque is needed on the 0.1 m arm; neglect lever weight. While F₂ is unknown, its arrowhead indicates direction only. Arms and apparatus remain unchanged throughout the steps.

Let's look at an example · 1

The first force's torque is 50·0,4 = 20 Н·м.

Calculate M₁l₁ = 0,4 мl₂ = 0,1 м50 НF₂ — ?M₁ = 50 · 0,4 = 20 Н·м
In the same apparatus, multiply 50 N by the 0.4 m moment arm. This gives M₁ = 20 Н·м, the first force's torque about the support.

Let's look at an example · 2

For equilibrium, the second torque must also be 20 N·m. Thus F₂ = 20/0,1 = 200 Н.

M₂ = M₁ = 20 Н·мl₁ = 0,4 мl₂ = 0,1 м50 Н200 НF₂ = 20 / 0,1 = 200 Н
The second force must produce an opposite torque of 20 N·m. On the same 0.1 m arm, F₂ = 200 Н. Both force arrows now use one scale: 200 N is four times 50 N.

Let's look at an example · 3

The moment arm is four times shorter, so the required force is four times greater.

The torques remain equall₁ = 0,4 мl₂ = 0,1 м50 Н200 НArm ÷ 4, force × 4
In the same apparatus, arms of 0.4 and 0.1 m have ratio 4 to 1; forces of 50 and 200 N have ratio 1 to 4. All lengths and force arrows agree with these ratios; the torques are equal.

Let's check the result

The force is 200 N: a moment arm four times shorter needs four times the force for the same torque.

Key idea · 1

Torque M = Fl depends on distance to the force's line of action; even a force applied far from the axis can have zero moment arm.

Key idea · 2

Equal opposite torques explain why a long moment arm lets a smaller force balance a larger one.

Key idea · 3

A fixed pulley changes pull direction; a movable pulley gains force at the cost of distance. A real machine requires extra input work.

Where do we go next?

For a real machine, we will compare useful work with total input and follow energy transformations.

Basic Concepts

3 concepts

Lever

A rigid object that can rotate about a support and transmit the effects of forces with different moment arms.

A longer moment arm lets a smaller force balance a larger force on a shorter arm.

Pulleys and the golden rule

Simple machines gain force at the cost of extra distance and ideally do not reduce the work required.

A fixed pulley changes force direction; an ideal movable pulley halves the required force.

Torque (moment of a force)

Force multiplied by its moment arm, a quantity describing the force's turning effect.

The moment arm is the shortest distance from the axis to the force's line of action, not simply the entire lever's length.

Physical quantities

2 quantities

Torque (moment of a force)

M

The product of force and its moment arm about the axis.

Unit: newton-metre · \mathrm{Н}\cdot\mathrm{м}

Moment arm

l

The shortest distance from the axis to the force's line of action.

Unit: meter · \mathrm{м}

Lesson formulas

2 formulas

Torque (moment of a force)

M = Fl

Torque magnitude equals force magnitude multiplied by the moment arm.

Lever equilibrium

F_1l_1 = F_2l_2

A lever is balanced when torques tending to rotate it in opposite directions are equal.

Test the relationship

Make a prediction first. The button changes the stated quantity; then compare the result and explore other values.

Lever and moment arm

F₁d₁ = F₂d₂

Massless rigid lever, fixed frictionless pivot, vertical forces. F₂ is calculated to ensure equilibrium; tilting is not modelled.

The right moment arm increases from 1 to 2 m. How will the balancing force F₂ change?

Your prediction

Initial values

Show vectors
F₁F₂d₁d₂N = F₁ + F₂

Calculated result

F₂
10 Н
M₁
10 Н·м
M₂
10 Н·м
N
20 Н
Explaining the result

Doubling the moment arm halves the required force. Moments, not forces alone, balance; the pivot reaction ensures vertical force balance.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.