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GRADE 8 · CHANGE IN STATE OF AGGREGATION

Evaporation, condensation and humidity

Saturated vapour and measuring relative humidity.

24 minutes7 theory cards
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Understanding step by step

A T-shirt dries even in a cool room, while drops appear on a cold glass. How do water molecules enter the air without boiling, and why do they sometimes return?

Room temperaturevapourWater enters the air without boilingDrops on fabric, molecules in air: schematic
A wet T-shirt dries in an ordinary room even though the water is far from boiling. Molecules leave the surface at any ordinary temperature.

Leaving the surface

Molecules at a liquid surface move at different speeds. Some have enough energy to overcome attraction to their neighbours and escape into the gas. Evaporation therefore occurs at the surface at any ordinary temperature at which the liquid exists; boiling is unnecessary. Imagine equal portions in a narrow glass and a wide saucer. The saucer has a larger surface from which molecules can escape, so, with other conditions equal, its water usually disappears faster.

evaporationcondensation
Evaporation occurs at the liquid surface. Arrows show molecules crossing its boundary: into the gas during evaporation and back into the liquid during condensation. There are no bubbles inside the liquid; a closed vessel and equilibrium are considered later.

Why the liquid cools

Why can wet skin feel cold? On average, escaping molecules carry away more energy than those remaining, reducing the liquid's internal energy. If the surroundings do not replace this energy, the liquid cools. Evaporation can also occur at constant temperature, with energy supplied by the air or a heater, for example. A lack of cooling therefore does not prove that evaporation has stopped.

Which molecules escape?more energetic on averageremaining liquidaverageenergy fallsIf no energy is supplied from outside
On average, escaping molecules carry more energy than those remaining. The mean energy of thermal motion in the liquid can therefore decrease. Arrows start at molecules near the surface. Cooling occurs if no external energy replaces the loss.

What controls the rate

Three changes help fabric dry: warming it, spreading it out and blowing air over it. Warming allows more molecules to escape; spreading the fabric exposes a larger surface. Moving air carries vapour away and reduces the number of molecules returning to the surface. To test one effect, keep the others unchanged. Wind alone does not make the water hotter: it changes the exchange of vapour between the surface and the surrounding air.

HeatingAreaWindlarger surfacecarries vapour awayWind reduces the return of moleculesKeep other conditions equal
Three factors, with other conditions equal: heating, a larger free surface and removal of humid air. Evaporation arrows start at the liquid surface; energy enters through the bottom. Wind removes vapour, reducing the return flow of molecules. The number of arrows does not specify a numerical ratio of rates.

The return flow

Vapour molecules also move continuously and sometimes return to the liquid. This reverse change from gas to liquid is called condensation. Close a vessel containing water at constant temperature: as vapour accumulates, returns become more frequent. If there is enough liquid and some remains, the average rates of evaporation and condensation become equal. The vapour is then saturated. If all the water disappears first, saturation may never be reached.

Closed vessel, T = constleaving and returningevaporationcondensationat equilibriumequal
Vapour molecules cross the surface and return to the liquid: this is condensation. In a closed vessel at constant temperature, the opposing flows eventually have equal average rates if there is enough liquid and some remains. The vapour is then saturated. Both paths reach the liquid surface.

Equilibrium is still active

At saturation, the amounts of liquid and vapour remain constant on average, but individual molecules keep crossing the boundary in both directions. This is dynamic equilibrium, not motion coming to a halt. The saturated vapour density ρнас is set by temperature; for water it increases on heating. After a temperature rise, the previous amount of vapour is therefore usually insufficient for saturation, and some additional liquid evaporates if liquid is available.

The processes do not stopevaporationcondensation=average ratesequalρнасT₁T₂T₃T₁ < T₂ < T₃: ρнас rises
At saturation, evaporation and condensation continue at equal average rates. Below, saturated vapour density is compared qualitatively at three temperatures T₁ < T₂ < T₃. The heights do not specify exact numbers or ratios: a higher temperature gives a higher equilibrium density.

Vapour compared with saturation

Two rooms can contain the same mass of water vapour per cubic metre yet be at different distances from saturation if their temperatures differ. Vapour density ρ is its mass per unit volume of air, in kg/m³ or g/m³. To assess the possibility of further evaporation and condensation, compare ρ with the saturated vapour density ρнас at the same temperature. This comparison defines relative humidity.

Same TSame T50%100%
Relative humidity compares water vapour density with saturated vapour density at the same temperature. The diagram represents 50% and 100% schematically.

Fractions and percentages

If the actual density is half the saturated density, relative humidity is one half, or 50%. In general, φ = ρ/ρнас; multiply this ratio by 100% to express it as a percentage. The density units must match so that they cancel. At constant temperature, doubling ρ doubles φ until saturation is reached. At ρ = 0 humidity is zero; at ρ = ρнас it is 100%. The latter means saturated vapour, not that all the air consists of water.

φ = ρ : ρнасρρнасnowsaturationφ = 0,5 → 50 %
The ratio of vapour density to saturated vapour density at the same temperature gives the fraction φ. Here the actual density is half the saturated value: measured from the same zero, the bar heights are in exactly the ratio 1:2. The fraction 0.5 corresponds to 50%.

Dew point

Cool air in a closed, rigid vessel while no droplets have yet formed. Vapour mass and volume stay constant, so ρ is unchanged while ρнас decreases. The ratio φ rises to one. This is the temperature at which condensation begins in this constant-volume experiment. The usual dew point is defined by cooling air at constant pressure and water-vapour content. With further cooling, some vapour can form droplets. Water on a cold glass thus comes from the surrounding air; it has not seeped through the glass.

Cooling at V = constT, °Cρ, г/м³ρнасρ before condensationstart ofcondensationcoolingThen some vapour becomes liquid
Schematic graph for cooling at constant volume with no vapour leakage. Before condensation, the actual density is constant: the red dashed line on the right. The condensation temperature in this experiment is where it intersects ρнас(T). The standard dew point is defined differently, at constant pressure and vapour content. On further cooling, some vapour condenses and its equilibrium density follows the blue curve; the red dashed line does not extend to the left.

Measuring humidity

A psychrometer has one dry thermometer and another wetted with water. In humid air, evaporation cools the wet thermometer less; in dry air, it cools it more. Humidity is found from both readings and a table appropriate to the instrument's operating conditions. At saturation, the readings are almost equal if the thermometers are correctly installed. Both the dry-bulb temperature and the difference between readings matter: the difference alone does not give a universal percentage.

DryWet22 °C010203016 °CReadings + table → humidity
Illustrative readings of two identical thermometers: dry bulb 22 °C, wet bulb 16 °C. Wet cloth surrounds the wet bulb; evaporation from it cools the instrument. The scales share the same zero and divisions. Humidity is found using the dry-bulb temperature, the difference between readings and a psychrometric table. In saturated air, evaporative cooling is almost absent.

Room humidity

The vapour density is 8 g/m³, and the saturated vapour density at the same temperature is 20 g/m³. Find the relative humidity.

Both densities at the same temperature0820ρ, г/м³ρнас, г/м³Relative humidity — ?
The actual vapour density is 8 g/m³; the saturated density at the same temperature is 20 g/m³. Both quantities use the same zero and scale, so bar heights are proportional to densities. Find the relative humidity. The same data and bars are kept throughout the steps.

Worked example · 1

Compare the vapour with saturated vapour at the same temperature. Both densities are in g/m³, so no unit conversion is needed in the ratio.

Both densities at the same temperature0820ρ, г/м³ρнас, г/м³(г/м³) / (г/м³) = 1A dimensionless ratio
The densities remain 8 and 20 g/m³ at the same temperature, with the same bars. Dividing g/m³ by g/m³ cancels the units. The ratio is a dimensionless number, not a density.

Worked example · 2

φ = 8/20 = 0,4; this is the fraction of the saturated density. Multiply by 100% to obtain 40%.

Both densities at the same temperature0820ρ, г/м³ρнас, г/м³φ = 8 / 20 = 0,4Still a fraction
For the same pair of bars, divide the actual density of 8 g/m³ by the saturated density of 20 g/m³ at the same temperature. φ = 8/20 = 0,4 is the fraction of saturation. The initial values, units, common zero and scale are unchanged.

Worked example · 3

At unchanged temperature, the vapour is still well below saturation: its density is four tenths of 20 g/m³. On cooling, the same vapour could have a different relative humidity.

Both densities at the same temperature0820ρ, г/м³ρнас, г/м³0,4 × 100% = 40%At this T, vapour is not yet saturated
The same densities, 8 and 20 g/m³, and their bar-height ratio are retained. Multiply the fraction 0.4 by 100% to obtain 40%. At this temperature, the actual density is below saturation, so the vapour is unsaturated. It is the ratio that is converted to a percentage; the bars still show densities.

Check the result

A relative humidity of 40% means that, at this temperature, the vapour density is 40% of its saturated value, not that vapour makes up 40% of the total air mass.

Key idea · 1

Evaporation and condensation occur simultaneously; the visible result depends on the difference between the molecular flows.

Key idea · 2

Saturation means equal average rates of the two processes with a liquid phase present.

Key idea · 3

Humidity depends on both vapour content and temperature; cooling can bring air to its dew point.

What comes next

During boiling, vapour also forms inside the liquid. Next, we will see how pressure affects this.

Basic Concepts

3 concepts

Saturated vapour

Vapour in dynamic equilibrium with a liquid at a given temperature: the average rates of evaporation and condensation are equal.

Molecules continue to cross in both directions. In a closed vessel, saturation is reached if there is enough liquid and some remains; all the liquid may evaporate before that happens. Saturated vapour density depends on temperature. Unsaturated vapour has a lower density than saturated vapour at the same temperature, and evaporation can exceed condensation.

Evaporation and condensation

Evaporation occurs from the surface of the liquid, and condensation turns the vapor back into liquid.

Heating, wind and increased surface area speed up evaporation; the fastest molecules carry energy away and cool the liquid.

Relative humidity

The ratio of the actual density of water vapor to the density of saturated vapor at the same temperature; to express it as a percentage, this ratio is multiplied by 100.

Dew point is the temperature to which the air must be cooled at constant pressure and water vapor content in order to achieve saturation. With further cooling, condensation may occur. Humidity is measured with a psychrometer or electronic sensor; densities are compared at the same temperature.

Physical quantities

3 quantities

Relative humidity

\varphi

The ratio of the actual density of water vapor to the density of saturated vapor at the same temperature; for percentages this ratio is multiplied by 100.

Unit: dimensionless quantity

Water vapor density

\rho

The mass of water vapor per unit volume of air.

Unit: kilogram per cubic meter · \frac{\mathrm{кг}}{\mathrm{м}^3}

Saturated vapor density

\rho_{\text{нас}}

The maximum equilibrium vapor density at a given temperature.

Unit: kilogram per cubic meter · \frac{\mathrm{кг}}{\mathrm{м}^3}

Lesson formulas

1 formula

Relative humidity

\varphi = \frac{\rho}{\rho_{\text{нас}}}

Relative humidity is equal to the ratio of the actual vapor density to the saturated vapor density.

Conditions: Both densities must be at the same temperature and in the same units. The formula gives a fraction; multiply the result by 100% to express it as a percentage.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.