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GRADE 8 · MAGNETIC PHENOMENA

Magnetic field action and motor

The Earth's field, the left-hand rule and the principle of the electric motor.

24 minutes7 theory cards
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Understanding step by step

A current-carrying wire deflects between magnetic poles. How can force on a straight wire rotate a loop, even when the forces on it sum to zero?

No currentCurrent on× — field away from usno magnetic forceIFmagnetic force upA motor uses this effect
The same horizontal wire lies in a field away from us. Without current there is no magnetic force. Current to the right gives upward force. This is force direction, not necessarily upward motion: motion also depends on other forces omitted here.

The field acts on current

Switch on current in a wire across a magnet's field. Moving charges experience magnetic force and transfer its effect to the wire through interactions with the material. A force arises perpendicular to current and field. Switch current off and this effect disappears even though the magnet remains. Distinguish this force on current from a magnet attracting iron: the wire need not be iron.

NSFI towards usB
B runs from N to S; I comes out of the page towards us. Magnetic force F points up, perpendicular to current and field.

The left-hand rule

Use the left-hand rule to check force direction. Hold the palm so B enters it, with four fingers along conventional current. The thumb held out at 90° indicates force. Reverse only current and force reverses; reverse only field and it also reverses; reverse both and force keeps its direction. Use conventional current, not the oppositely directed electron motion.

B enters the palmIFB — into palm4 fingers — Ithumb — FUse conventional current, not electron flow
Field lines enter the open left palm; four fingers show conventional current, and the extended thumb shows force direction.

Three ways to increase force

What sets the strength of the deflection? For a wire across the field, a stronger field, more current or a longer section in the field each increases the force. Magnetic flux density B characterises the field and is measured in teslas, T. Active length l, in metres, includes only wire inside the field considered; F is in N. Supply leads outside the field are not part of this length.

What increases forcestronger fieldB, Тлmore currentI, Аlonger sectionl, мChange one factor, keep the others
For a straight section across a uniform field, increasing B, I or active length l increases force if other quantities stay unchanged. l is only the wire portion inside the field, not the whole wire.

A simple calculation case

For a straight section perpendicular to a uniform field, these relationships combine as F = BIl. Doubling B, I or active length separately doubles F; at zero current F is zero. With B in T, I in A and l in m, the result is N. Rotating the wire changes the result: along the field lines this force vanishes. Do not use F = BIl for an arbitrary tilted section and ignore perpendicularity.

F = B · I · lBteslaIampereslmetresthe result is newtonsWhat if the wire runs along the field?wire along the field —no force of this kind
For a straight wire across a uniform field, force is flux density times current times section length: teslas, amperes and metres give newtons.

Why a loop rotates

Bend the wire into a loop. Opposite sides carry opposite currents, so magnetic forces are opposite too. They may seem to cancel completely. But they act at different places and can create torque, like turning a steering wheel with two hands. Their sum can be zero while a turning effect remains. Its magnitude depends on loop orientation and the forces' lever arms.

View along the rotation axisNSBaxisF₁F₂Zero net force, nonzero torque
View along the rotation axis: the loop is edge-on; circles are cross-sections of its two long sides. At left, current is towards us and force up; at right, current is away and force down. B runs from N to S. Equal opposite forces on opposite sides of the axis give clockwise torque with zero net force. The source and commutator are omitted.

Keep the rotation going

With current direction unchanged, a loop tends towards a particular orientation rather than rotating endlessly one way. In a simple commutator motor, current reverses every half-turn so the forces support rotation again after passing that orientation. Inertia and motor design help it pass through. Electrical energy becomes mechanical work, with some lost to heating and other processes.

nowAfter half a turnАБ+−'+' brush on АБА+−'+' brush on БGaps separate the half-ringsrotation continues the same way
Half-rings А and Б are insulated from one another by gaps and rotate with the loop; colours identify the half-rings. After a half-turn the fixed brushes swap contacts А↔Б, reversing loop current. Only the commutator is shown. Electrical energy becomes mechanical work and heat.

Earth and the compass

Why does a compass work far from a laboratory magnet? Earth's magnetic field aligns it. Its north end usually points roughly towards geographic north. External field lines enter Earth there, so this region acts with magnetic south polarity and attracts the needle's north end. Magnetic and geographic poles do not coincide; a compass is therefore not an infallible guide to geographic north.

Geographic northSNEarthAxis tilt is schematicTop viewnorthcompassapproximatelytowards north
Left: a simplified dipole model of Earth's field. External lines enter the northern hemisphere, which has magnetic south polarity S. Grey is the geographic axis; green dashed is the magnetic axis; the tilt is schematic. Right: a separate horizontal compass. Its red north end follows the local field's horizontal component and only approximately points to geographic north.

What can distort the reading

Bring a magnet or current-carrying wire near a compass and the needle can deflect markedly. It responds to the local combined field, not specifically to Earth alone. Iron objects can also change this field. Test a compass away from unwanted magnetic influences. If it turns unexpectedly, first look for a nearby field change, not a shift of the geographic pole.

Compass in different conditionsundisturbedroughly northIwire carrying currentneedle deflectedSNnearby magnetneedle deflectedA compass shows the local field
Top view. Left: no strong local field sources. Centre: a wire beneath the compass carries northward current, deflecting the needle east. Right: beneath the magnet's centre, its field points left; combined with Earth's field it deflects the north end left. Angles are schematic; iron objects can also distort the local field.

Force on a straight wire

In a uniform field B = 0,2 Тл, a 0.1 m section carrying 3 A lies perpendicular to the field lines. Find the force magnitude.

Known quantities× — field away from usB = 0,2 ТлI = 3 Аl = 0,1 мWire perpendicular to fieldForce magnitude — ?
A 0.1 m section carrying 3 A lies in a uniform 0.2 T field. The bracket marks the full active length. The given condition is that the wire is perpendicular to B; page directions are chosen for illustration, not additional problem data.

Worked example · 1

Find force magnitude on the 0.1 m active section. The field is uniform and the wire is perpendicular, so F = BIl applies.

Check the conditions× — field away from usB = 0,2 ТлI = 3 Аl = 0,1 мWire ⟂ uniform fieldF = B · I · l
The same setup: uniform field, the full marked section inside it, and wire perpendicular to B. Thus F = BIl gives force magnitude. Wire position and B, I, l stay unchanged.

Worked example · 2

F = 0,2·3·0,1 = 0,06 Н. Doubling active length at the same current and field would double force.

Substitute the numbers× — field away from usB = 0,2 ТлI = 3 Аl = 0,1 мF = 0,2 · 3 · 0,1F = 0,06 Н
For the same section, F = 0,2 Тл · 3 А · 0,1 м = 0,06 Н. The product Тл·А·м gives newtons. This is force magnitude; field and current directions in the drawing remain illustrative choices.

Worked example · 3

This product does not determine force direction. The left-hand rule needs field and current directions; the problem asks only for magnitude.

For the I and B drawn here× — field away from usB = 0,2 ТлI = 3 Аl = 0,1 мFMagnitude from the data: 0,06 НDirection requires I and B
In the drawing's chosen orientation, current is up and B away from us, so force is left. But the problem specifies only magnitudes and mutual perpendicularity: page direction cannot be inferred from 0.06 N alone. Reversing current would reverse it.

Check the result

The force magnitude is 0.06 N. It acts on the specified wire section, not the full circuit length.

Key idea · 1

F = BIl describes a straight section across a uniform field; current and field set the direction.

Key idea · 2

Separated opposite forces can rotate a loop even with zero net force.

Key idea · 3

A motor maintains rotation by switching current; a compass follows the local combined field.

What comes next

Next we reverse cause and effect: moving a magnet can produce a voltage.

Basic Concepts

3 concepts

Action of the field on the conductor

A magnetic field exerts a force on a current-carrying conductor if the current is not directed along the field lines.

Use the left-hand rule with current direction and magnetic flux density direction to find the force direction.

Electric motor

A device that converts electrical energy into mechanical energy due to the action of a magnetic field on a current.

Forces on opposite sides of the loop produce torque; switching current direction maintains rotation.

Earth's magnetic field

The Earth creates a magnetic field that orients the compass needle approximately along the magnetic meridian.

The magnetic and geographic poles do not coincide, and the field partially protects the atmosphere from charged particles from the Sun.

Physical quantities

3 quantities

Magnetic flux density

B

Strength characteristics of the magnetic field.

Unit: tesla · \mathrm{Тл}

Force on conductor

F

The magnetic field force acting on a current-carrying conductor.

Unit: newton · \mathrm{Н}

Conductor length in field

l

The length of a section of conductor located in a magnetic field.

Unit: metre · \mathrm{м}

Lesson formulas

1 formula

Force on a current-carrying conductor

F = BIl

For a perpendicular wire, force is magnetic flux density times current times active wire length.

Conditions: The conductor is perpendicular to the lines of a uniform magnetic field.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.