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GRADE 11 · MAGNETISM

Magnetic flux and induction

Flux, electromagnetic induction, self-induction and field energy.

30 minutes18 theory cards
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Understanding step by step

A magnet resting beside a coil does not by itself produce a steady current. Move the magnet and the meter deflects. What changed: field strength, the number of field lines or the circuit’s geometry? We need a quantity that combines these changes.

Magnet at rest and in motionNSstoppedΦ unchangedNSmovesΦ changesWhich quantity changed?
Beside a stationary magnet, flux through the coil is constant and the meter shows no response. Moving the magnet changes the flux and produces a response.

Field through a loop

Rotate a loop in the same field. The field’s contribution through its surface is greatest when perpendicular to the plane; when it lies in the plane, its normal component is zero. Magnetic flux accounts for field, area and surface orientation together. Measure the angle from a chosen normal, an arrow perpendicular to the loop. Thinking of field passing through an area is useful, but no substance is flowing through the opening.

Flux depends on orientationnormal along Bmaximum fluxtiltless fluxfield in the planezero fluxnormal: perpendicular to the loop’s plane
Flux uses the normal, an arrow perpendicular to the loop’s plane. Flux is greatest when the normal points along the field, and zero when the field lies in the plane.

Angle to the normal

For a flat surface in a uniform field, \Phi=BS\cos\alpha, where α is between B and the chosen normal. B is in teslas and S in m². Doubling area doubles flux; turning to α=90° makes it zero, while at α=0° it equals BS. Cosine appears because we need the normal field component. Do not substitute the angle to the plane, or the angle to current used in the force law: the geometry is different.

αnBSΦ = BS cos α
Flux through a flat surface is BS cos α, where α is the angle between the field and the surface normal. If the field lies along the surface, flux is zero.

The unit of flux

Magnetic flux is measured in webers: 1\,\mathrm{Вб}=1\,\mathrm{Тл}\cdot\mathrm{м}^2=1\,\mathrm{В}\cdot\mathrm{с}. Choosing the opposite normal reverses the sign of Φ, without reversing the physical field. Keep the same normal when comparing different times. Flux can be negative by convention, like a velocity component; that does not mean negative area or no field.

1 Вб = 1 Тл·м² = 1 В·сnormal upΦ > 0normal downΦ < 0same magnitude; the normal sets the sign
Flux is measured in webers, equivalent to tesla times square metre or volt-second. Reversing the normal changes the sign of flux, but not its magnitude.

Change produces an EMF

Changing B, loop area or tilt can change flux. Electromagnetic induction is the appearance of an EMF when flux through a circuit changes. In a stationary circuit a changing magnetic field causes it; in a moving circuit magnetic force on charges can contribute. Current requires a closed conducting path. Breaking the circuit may stop current without preventing an EMF from arising.

EMF does not always mean currentchange field, area or tiltopen circuitEMF, no currentclosed circuitcurrent flowschanging flux produces induction
Changing flux produces an EMF around a circuit, but current requires a closed path. An open circuit can have an EMF without a current.

Average EMF

For n turns with equal flux through each, \mathcal E_i=n|\Delta\Phi|/\Delta t gives the magnitude of the average EMF over an interval. ΔΦ is final minus initial flux in webers, Δt is in seconds and n is dimensionless; the answer is in volts. Doubling the number of identical turns doubles the EMF. Zero total flux change means zero signed average EMF, although an EMF may arise and reverse during the interval.

εi = n |ΔΦ| / ΔtΦsame flux through every turnn: turn count, dimensionlessEMF is in volts
Flux is the same through each turn, so turn count multiplies the coil’s response. The magnitude of average EMF is measured in volts.

Faster change, greater response

Make the same flux change slowly, then twice as fast. The magnitude of average EMF doubles in the second experiment: both change and time matter. If flux changes linearly, average and instantaneous EMFs agree. Otherwise the instantaneous value can be above or below average. Magnitude of the average and average magnitude differ if direction changes during the interval; the endpoint difference misses such oscillations.

Same ΔΦ, different timesΔΦquicklylarger EMFΔΦslowlysmaller EMFthe formula averages the whole interval
The same flux change in less time gives a larger average EMF magnitude. For a nonuniform change, the formula averages over the entire interval.

Opposing the change

Which way does induced current flow in a closed loop? Lenz’s law says its field opposes the change in the original flux. It contributes an opposing flux during an increase, and supports the original direction during a decrease. If the response reinforced its cause without work, energy could grow by itself. Moving the magnet therefore requires work. The opposition is to the change, not always to the original field itself.

SNNSApproaching
The magnet’s north pole approaches the coil. Induced current opposes the increasing flux: the coil’s near face becomes a north pole. Once the magnet stops, this induced current dies away.

A coil acts on itself

A coil’s current creates its own field. A changing current changes the flux linked to the coil, producing a self-induced EMF. This opposes both increases and decreases in current, tending to preserve the previous state. Inductance L, measured in henries, describes the link. A larger L gives a greater EMF for the same rate of current change. Self-induction requires no motion relative to an external magnet.

Current does not change instantlyswitch oncurrent rises graduallyswitch offcurrent decays graduallyinductance L is measured in henries
A coil’s own flux changes with its current. The resulting EMF opposes both current rise and current decay. Inductance describes this response.

Flux linkage

One turn encloses flux Φ; n identical turns have total flux linkage nΦ. For a linear coil, n\Phi=LI. Doubling current doubles flux linkage at constant L; for one turn, Φ=LI. This sums contributions over turns rather than representing two different fields. Once nΦ is used, do not multiply by n again: that counts the turns twice. A nonlinear core can make L vary.

n Φ = L Iflux Φ through one turnnΦ: flux linkage= L Ifor one turn, Φ = L Ido not multiply by n twice
The sum of fluxes through all turns is called flux linkage. For a linear coil it is proportional to current. Do not multiply by the number of turns a second time.

Changing its own current

Substitute the flux–current relation into the induction law. At constant L, \mathcal E_{\text{си}}=L|\Delta I|/\Delta t. With ΔI in amperes, the result is the magnitude of average EMF in volts. The same current change in half the time gives twice the EMF. Use Lenz’s law for direction. If current rises and falls, the endpoint difference determines the signed average, not the sum of every short voltage spike.

I increasesSelf-induced EMFL
As current rises, the coil’s own magnetic flux increases. Self-induced EMF opposes the current rise. Energy LI²/2 is stored in the coil’s magnetic field.

Stored magnetic energy

As the source increases current, it works against self-induction. A linear coil stores magnetic energy W=LI^2/2 in joules. Doubling I multiplies energy by four; doubling L at the same I doubles energy. Current sign does not affect it. At I=0 this energy store is absent. As current falls, the field can return energy to the circuit. Self-induction describes energy exchange, not the creation of an extra energy source.

W = L I² / 2Wcurrent I4Wcurrent 2Ienergy returns as current decreases
The source works against self-induction, storing energy in the coil’s field. Doubling current quadruples the store; when current falls, energy returns to the circuit.

A moving rod

Move a straight rod through a field: force on its moving charges separates them along the rod. If the rod lies along v×B, \mathcal E=Blv\sin\alpha, where α is the angle between velocity and B, l is in metres and v in metres per second. Doubling speed doubles EMF; motion along the field gives zero. For another rod orientation, project the force along it. Without this condition, the formula could predict a voltage between the wrong endpoints.

+−vl⊗ B
A rod moves right through a field into the page. Magnetic force pushes positive charges up and negative charges down, producing EMF Blv between its ends.

A rotating loop

Uniform rotation makes a loop’s flux vary periodically and generates an alternating EMF. For n identical turns, \mathcal E_{\max}=nBS\omega, with ω in radians per second. Rotating twice as fast doubles both frequency and EMF amplitude. The axis lies in the loop’s plane and is perpendicular to uniform B. Maximum EMF occurs when flux changes fastest, not when flux itself is greatest: these occur at different points in the cycle.

εmax = n B S ωBaxisuniform rotationω: angular speed, рад/с
A loop rotating uniformly in a uniform field changes its flux periodically. Maximum EMF depends on turn count, field, area and angular speed.

Work through the example

A coil has 100 turns. Flux through each falls uniformly from 0.003 to 0.001 Wb in 0.1 s. Find the EMF magnitude.

Known quantities100 turnsflux decreasesΦ₁ = 0,003 ВбΦ₂ = 0,001 ВбΔt = 0,1 сn = 100EMF magnitude — ?
In a hundred-turn coil, flux through each turn falls uniformly from three thousandths to one thousandth of a weber in one tenth of a second. Find the EMF magnitude.

Worked example · 1

Flux changes identically through each of the 100 turns. Find the change for one turn, then multiply by n once.

Which law applies?changing fluxεi = n |ΔΦ| / Δtmoving rodε = B l vnot needed heregiven: flux change and turn counttherefore use Faraday’s law
Flux change through one turn and the number of turns are given, so use the law of electromagnetic induction.

Worked example · 2

|ΔΦ| = |0,001 − 0,003| = 0,002 Вб. Flux decreases, but we use the positive magnitude of its change to find the EMF magnitude.

Flux change|ΔΦ| = |0,001 − 0,003|0,002 Вбuse Lenz’s law separately for the sign
Subtract initial flux from final flux and take the magnitude: two thousandths of a weber.

Worked example · 3

|ε| = n|ΔΦ|/Δt = 100 × 0,002/0,1 = 2 В.

Calculate the EMF100 · 0,002 / 0,12 Вwebers per second give volts
Multiply turn count by the flux-change magnitude and divide by time to obtain two volts.

Worked example · 4

The change is uniform, so 2 V is also the instantaneous EMF magnitude over this interval. In a closed circuit, the induced field would support the decreasing flux.

Checkuniform changeaverage = instantaneousflux decreasescurrent supports itLenz: current opposes the change
Flux changes uniformly, so average and instantaneous EMF agree. In a closed circuit, induced current would support the decreasing flux.

Check the result

EMF magnitude: |ε| = 2 В. It is constant over the stated interval because flux decreases uniformly.

Key point · 1

EMF is linked to changing flux, which depends on field, area and orientation. Constant flux gives no induced EMF.

Key point · 2

Lenz’s law specifies opposition to change and makes induction consistent with energy conservation.

Key point · 3

A coil links current to flux linkage and stores LI²/2. Do not count its turns twice.

Where do we go next?

Next we explore energy exchange in periodic motion.

Basic Concepts

2 concepts

Electromagnetic induction

The occurrence of EMF in a circuit when the magnetic flux through it changes.

An EMF arises from changing magnetic flux. By Lenz’s law, the induced current opposes that change.

Self-induction

The occurrence of EMF in a circuit when its own current and magnetic flux change.

A coil opposes rapid changes in its own current. Greater inductance or a greater rate of current change produces a greater EMF.

Physical quantities

8 quantities

Magnetic flux

\Phi

A measure of the magnetic field passing through a surface.

Unit: weber · \mathrm{Вб}

induced emf

\mathcal{E}_i

EMF that occurs when magnetic flux changes.

Unit: volt · \mathrm{В}

Number of turns

n

The number of turns of conductor in a coil.

Unit: dimensionless quantity

Magnetic flux change

\Delta\Phi

The difference between the final and initial magnetic fluxes.

Unit: weber · \mathrm{Вб}

Inductance

L

The ability of a circuit to create its own magnetic flux when current passes.

Unit: henry · \mathrm{Гн}

Current change

\Delta I

The difference between the final and initial currents.

Unit: ampere · \mathrm{А}

Self-induced EMF

\mathcal{E}_{\text{си}}

EMF arising due to changes in current in the circuit itself.

Unit: volt · \mathrm{В}

Magnetic field energy

W

The energy stored in the magnetic field of the coil.

Unit: joule · \mathrm{Дж}

Lesson formulas

8 formulas

Magnetic flux

\Phi=BS\cos\alpha

Magnetic flux depends on magnetic flux density, area and surface orientation.

Definition of the weber

1\,\mathrm{Вб}=1\,\mathrm{В}\cdot\mathrm{с}=1\,\mathrm{Тл}\cdot\mathrm{м}^2

One weber is equal to a volt-second and a tesla-square meter.

Law of Electromagnetic Induction

\mathcal{E}_i=n\frac{\lvert\Delta\Phi\rvert}{\Delta t}

The right-hand side gives the magnitude of the average EMF over the interval. Lenz’s law determines direction; instantaneous signed EMF is −n dΦ/dt.

Conditions: Each of n turns has the same flux and n is constant. For a constant rate of flux change, the result also equals the instantaneous EMF magnitude. In general, the magnitude of average EMF differs from the average of its magnitude.

Self-induced EMF

\mathcal{E}_{\text{си}}=L\frac{\lvert\Delta I\rvert}{\Delta t}

The magnitude of average self-induced EMF is proportional to current change per unit time. Its direction opposes the current change; instantaneous signed EMF is −L dI/dt.

Conditions: Inductance L is constant. The finite-difference expression gives the instantaneous EMF magnitude exactly when the rate of current change is constant.

Magnetic energy of a coil

W=\frac{LI^2}{2}

The energy of the magnetic field depends on the inductance and the square of the current.

Motional EMF in a conductor

\mathcal{E}=Blv\sin\alpha

EMF occurs when a conductor moves in a magnetic field.

Maximum EMF of a rotating loop

\mathcal{E}_{\max}=nBS\omega

The loop’s EMF amplitude is proportional to turn count, magnetic flux density, area and angular speed.

Flux linkage and inductance

n\Phi=LI

Inductance relates current to a coil’s flux linkage, the sum of magnetic fluxes through all its turns.

Conditions: Each of n turns has the same flux. The product nΦ is called flux linkage; for one turn, Φ = LI.

Test the relationship

Make a prediction first. The button changes the stated quantity; then compare the result and explore other values.

Rotating coil and emf

Φ = BS cos(ωt); ε = −N dΦ/dt = NBSω sin(ωt); N = 100

100 identical turns in a uniform field; constant rotation rate. Φ is flux through one turn. The circuit is open; current and reaction torque are not modelled.

Rotation frequency increases from 1 to 2 Hz. How will the emf amplitude change?

Your prediction

Initial values

Show vectors
nBN = 100; Φ = BS cos(ωt)
0-15.580.5-7.791101.57.791215.58ε, Вt, с
ε

Calculated result

Φ
0.02 Вб
ε
0 В
εмакс
12.57 В
Explaining the result

Emf depends on the rate of flux change. When |Φ| is largest, ε = 0; at Φ = 0, |ε| is largest. Doubling ν doubles the emf amplitude.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.