GRADE 10 PRACTICE
Physics Problems: SI and magnitude scales, Grade 10
Units, conversions and prefixes.
Here the conditions and analysis of the solution can be read without an account. In the simulator, you need to collect the same analyzes yourself: “Given,” formulas, order of steps and answer.
Problem statements
The answer options are there to check against, and the walkthrough opens under each problem.
Problem #117
SI units and unit conversionsWire length 250 cm. Express it in meters.
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- l
- 250\,\text{см}
x - ?
- x=\frac{l}{100}x=\frac{250}{100}x=2{,}5\,\text{м}
The prefix centi means one hundredth.
Answer2{,}5\,\text{м}
Problem #118
SI units and unit conversionsWire length 480 cm. Express it in meters.
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- l
- 480\,\text{см}
x - ?
- x=\frac{l}{100}x=\frac{480}{100}x=4{,}8\,\text{м}
The prefix centi means one hundredth.
Answer4{,}8\,\text{м}
Problem #119
SI units and unit conversionsA rectangular plate has sides 20 cm and 30 cm. Find the area in m².
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- a
- 20\,\text{см}
- b
- 30\,\text{см}
A - ?
- S=abS=20 \cdot 30S=600\,\text{см}^{2}
First, we calculate the area in the original units.
- A=\frac{S}{10^4}A=\frac{600}{10000}A=0{,}06\,\text{м}^{2}
The length conversion factor is squared.
Answer0{,}06\,\text{м}^{2}
Problem #120
SI units and unit conversionsA rectangular plate has sides 30 cm and 40 cm. Find the area in m².
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- a
- 30\,\text{см}
- b
- 40\,\text{см}
A - ?
- S=abS=30 \cdot 40S=1200\,\text{см}^{2}
First, we calculate the area in the original units.
- A=\frac{S}{10^4}A=\frac{1200}{10000}A=0{,}12\,\text{м}^{2}
The length conversion factor is squared.
Answer0{,}12\,\text{м}^{2}
Problem #121
SI units and unit conversionsSample mass 54 g has volume 20 cm³. Find its density in kg/m³.
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- m
- 54\,\text{г}
- V
- 20\,\text{см}^{3}
\rho - ?
- M=\frac{m}{1000}M=\frac{54}{1000}M=0{,}054\,\text{кг}
Convert the mass to kilograms.
- v=\frac{V}{10^6}v=\frac{20}{1000000}v=0{,}00002\,\text{м}^{3}
The length conversion factor is cubed.
- \rho=\frac{M}{v}\rho=\frac{0{,}054}{0{,}00002}\rho=2700\,\text{кг/м}^{3}
We use both quantities in SI.
Answer2700\,\text{кг/м}^{3}
Problem #122
SI units and unit conversionsSample mass 156 g has volume 20 cm³. Find its density in kg/m³.
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- m
- 156\,\text{г}
- V
- 20\,\text{см}^{3}
\rho - ?
- M=\frac{m}{1000}M=\frac{156}{1000}M=0{,}156\,\text{кг}
Convert the mass to kilograms.
- v=\frac{V}{10^6}v=\frac{20}{1000000}v=0{,}00002\,\text{м}^{3}
The length conversion factor is cubed.
- \rho=\frac{M}{v}\rho=\frac{0{,}156}{0{,}00002}\rho=7800\,\text{кг/м}^{3}
We use both quantities in SI.
Answer7800\,\text{кг/м}^{3}
Problem #123
Decimal prefixesWire length 250 cm. Express it in meters.
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- l
- 250\,\text{см}
x - ?
- x=\frac{l}{100}x=\frac{250}{100}x=2{,}5\,\text{м}
The prefix centi means one hundredth.
Answer2{,}5\,\text{м}
Problem #124
Decimal prefixesWire length 480 cm. Express it in meters.
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- l
- 480\,\text{см}
x - ?
- x=\frac{l}{100}x=\frac{480}{100}x=4{,}8\,\text{м}
The prefix centi means one hundredth.
Answer4{,}8\,\text{м}
Problem #125
Decimal prefixesA rectangular plate has sides 20 cm and 30 cm. Find the area in m².
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- a
- 20\,\text{см}
- b
- 30\,\text{см}
A - ?
- S=abS=20 \cdot 30S=600\,\text{см}^{2}
First, we calculate the area in the original units.
- A=\frac{S}{10^4}A=\frac{600}{10000}A=0{,}06\,\text{м}^{2}
The length conversion factor is squared.
Answer0{,}06\,\text{м}^{2}
Problem #126
Decimal prefixesA rectangular plate has sides 30 cm and 40 cm. Find the area in m².
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- a
- 30\,\text{см}
- b
- 40\,\text{см}
A - ?
- S=abS=30 \cdot 40S=1200\,\text{см}^{2}
First, we calculate the area in the original units.
- A=\frac{S}{10^4}A=\frac{1200}{10000}A=0{,}12\,\text{м}^{2}
The length conversion factor is squared.
Answer0{,}12\,\text{м}^{2}
Problem #127
Decimal prefixesSample mass 54 g has volume 20 cm³. Find its density in kg/m³.
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- m
- 54\,\text{г}
- V
- 20\,\text{см}^{3}
\rho - ?
- M=\frac{m}{1000}M=\frac{54}{1000}M=0{,}054\,\text{кг}
Convert the mass to kilograms.
- v=\frac{V}{10^6}v=\frac{20}{1000000}v=0{,}00002\,\text{м}^{3}
The length conversion factor is cubed.
- \rho=\frac{M}{v}\rho=\frac{0{,}054}{0{,}00002}\rho=2700\,\text{кг/м}^{3}
We use both quantities in SI.
Answer2700\,\text{кг/м}^{3}
Problem #128
Decimal prefixesSample mass 156 g has volume 20 cm³. Find its density in kg/m³.
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- m
- 156\,\text{г}
- V
- 20\,\text{см}^{3}
\rho - ?
- M=\frac{m}{1000}M=\frac{156}{1000}M=0{,}156\,\text{кг}
Convert the mass to kilograms.
- v=\frac{V}{10^6}v=\frac{20}{1000000}v=0{,}00002\,\text{м}^{3}
The length conversion factor is cubed.
- \rho=\frac{M}{v}\rho=\frac{0{,}156}{0{,}00002}\rho=7800\,\text{кг/м}^{3}
We use both quantities in SI.
Answer7800\,\text{кг/м}^{3}
The theory behind these problems
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Formulas by topic
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