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GRADE 8 PRACTICE

Physics Problems: Resistance and Ohm's Law, Grade 8

Conductor resistance, Ohm's law and rheostat.

18 problems across 4 sub-topics
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Problem statements

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18 problems
Position in this set: 1 from 18

Problem #43

Resistance and Ohm's Law

What concept does the description correspond to: “One ohm is the resistance of the section in which a voltage of one volt creates a current of one ampere.»?

Answer options

  1. \text{Ом}
  2. \text{Ohm's law for a circuit section}
  3. \text{Electrical resistance}
  4. \text{Capillary action}
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Given
\text{Description}
\text{One ohm is the resistance of the section in which a voltage of one volt creates a current of one ampere.}
Find

\text{name concepts}

  1. \text{Let's compare approval with definition}

    The unit relates the readings of the ammeter and voltmeter through Ohm's law.

  2. \text{Let's formulate conclusion}\text{Concept} = \text{Ом}

Answer\text{Concept} = \text{Ом}

Position in this set: 2 from 18

Problem #44

Resistance and Ohm's Law

What concept does the description correspond to: “For an ohmic section under constant physical conditions, current is proportional to voltage: I = U/R, where R is constant over the range considered.»?

Answer options

  1. \text{Ohm's law for a circuit section}
  2. \text{Ом}
  3. \text{Electrical resistance}
  4. \text{Capillary action}
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Given
\text{Description}
\text{For an ohmic section under constant physical conditions, current is proportional to voltage: I = U/R, where R is constant over the range considered.}
Find

\text{name concepts}

  1. \text{Let's compare approval with definition}

    The graph of I(U) of such a section is a straight line through the origin. Heating can change R. However, constant temperature alone is not enough: the diode and some other elements remain non-ohmic, so the applicability of the dependence with constant R is tested by experiment.

  2. \text{Let's formulate conclusion}\text{Concept} = \text{Ohm's law for a circuit section}

Answer\text{Concept} = \text{Ohm's law for a circuit section}

Position in this set: 3 from 18

Problem #45

Ohm's law

A 6 ohm resistor maintains a voltage of 12 V. Find the current.

Answer options

  1. 2\,\text{А}
  2. 0{,}5\,\text{А}
  3. 6\,\text{А}
  4. 72\,\text{А}
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Given
R
6\,\text{Ом}
U
12\,\text{В}
Find

I

  1. I=\frac{U}{R}I=\frac{12}{6}\,\text{А}I = 2\,\text{А}

Answer2\,\text{А}

Position in this set: 4 from 18

Problem #46

Conductor resistance and rheostat

What concept does the description correspond to: “The resistance of a homogeneous conductor increases with length, decreases with cross-sectional area and depends on the material.»?

Answer options

  1. \text{Conductor resistance}
  2. \text{Resistivity}
  3. \text{Rheostat}
  4. \text{Capillary action}
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Given
\text{Description}
\text{The resistance of a homogeneous conductor increases with length, decreases with cross-sectional area and depends on the material.}
Find

\text{name concepts}

  1. \text{Let's compare approval with definition}

    A long, thin wire has more resistance than a short, thick wire of the same material.

  2. \text{Let's formulate conclusion}\text{Concept} = \text{Conductor resistance}

Answer\text{Concept} = \text{Conductor resistance}

Position in this set: 5 from 18

Problem #47

Conductor resistance and rheostat

What concept does the description correspond to: “A characteristic of a material that relates the resistance of a conductor to its length and cross-sectional area.»?

Answer options

  1. \text{Resistivity}
  2. \text{Conductor resistance}
  3. \text{Rheostat}
  4. \text{Capillary action}
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Given
\text{Description}
\text{A characteristic of a material that relates the resistance of a conductor to its length and cross-sectional area.}
Find

\text{name concepts}

  1. \text{Let's compare approval with definition}

    Copper's low resistivity makes it useful for wiring; alloys with greater resistivity are useful for heaters.

  2. \text{Let's formulate conclusion}\text{Concept} = \text{Resistivity}

Answer\text{Concept} = \text{Resistivity}

Position in this set: 6 from 18

Problem #48

Conductor resistance

A wire 10 m long and with a cross-sectional area of 2 mm² has a resistivity of 0.5 Ohm mm²/m. Find resistance.

Answer options

  1. 2{,}5\,\text{Ом}
  2. 0{,}1\,\text{Ом}
  3. 5\,\text{Ом}
  4. 25\,\text{Ом}
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Given
\rho
0{,}5\,\text{Ом}\cdot\text{мм}^{2}/\text{м}
l
10\,\text{м}
S
2\,\text{мм}^{2}
Find

R

  1. R=\rho\frac{l}{S}R=0{,}5\cdot\frac{10}{2}\,\text{Ом}R = 2{,}5\,\text{Ом}

Answer2{,}5\,\text{Ом}

Position in this set: 7 from 18

Problem #157

Resistance and Ohm's Law

Resistor voltage 12 V, resistance 4 Ohm. Find the current.

Answer options

  1. 3\,\text{А}
  2. 6\,\text{А}
  3. 1{,}5\,\text{А}
  4. 9\,\text{А}
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Given
U
12\,\text{В}
R
4\,\text{Ом}
Find

I

  1. I=\frac{U}{R}I=\frac{12}{4}I=3\,\text{А}

    We apply Ohm's law to a section of the circuit.

Answer3\,\text{А}

Position in this set: 8 from 18

Problem #158

Resistance and Ohm's Law

Resistor voltage 24 V, resistance 6 Ohm. Find the current.

Answer options

  1. 8\,\text{А}
  2. 4\,\text{А}
  3. 2\,\text{А}
  4. 12\,\text{А}
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Given
U
24\,\text{В}
R
6\,\text{Ом}
Find

I

  1. I=\frac{U}{R}I=\frac{24}{6}I=4\,\text{А}

    We apply Ohm's law to a section of the circuit.

Answer4\,\text{А}

Position in this set: 9 from 18

Problem #159

Resistance and Ohm's Law

Under tension 6 The ammeter shows 200 mA. Find the resistance of the circuit section.

Answer options

  1. 60\,\text{Ом}
  2. 30\,\text{Ом}
  3. 15\,\text{Ом}
  4. 90\,\text{Ом}
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Given
U
6\,\text{В}
i
200\,\text{мА}
Find

R

  1. I=\frac{i}{1000}I=\frac{200}{1000}I=0{,}2\,\text{А}

    Before calculating, we convert milliamps to amperes.

  2. R=\frac{U}{I}R=\frac{6}{0{,}2}R=30\,\text{Ом}

    We express resistance from Ohm's law.

Answer30\,\text{Ом}

Position in this set: 10 from 18

Problem #160

Resistance and Ohm's Law

Under tension 12 The ammeter shows 300 mA. Find the resistance of the circuit section.

Answer options

  1. 80\,\text{Ом}
  2. 20\,\text{Ом}
  3. 40\,\text{Ом}
  4. 120\,\text{Ом}
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Given
U
12\,\text{В}
i
300\,\text{мА}
Find

R

  1. I=\frac{i}{1000}I=\frac{300}{1000}I=0{,}3\,\text{А}

    Before calculating, we convert milliamps to amperes.

  2. R=\frac{U}{I}R=\frac{12}{0{,}3}R=40\,\text{Ом}

    We express resistance from Ohm's law.

Answer40\,\text{Ом}

Position in this set: 11 from 18

Problem #161

Resistance and Ohm's Law

Under tension 12 V through a resistor for 10 s charge passed 20 Cl. What current will be at voltage 30 Q, if the resistance does not change?

Answer options

  1. 10\,\text{А}
  2. 2{,}5\,\text{А}
  3. 5\,\text{А}
  4. 15\,\text{А}
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Given
U_1
12\,\text{В}
t
10\,\text{с}
q
20\,\text{Кл}
U_2
30\,\text{В}
Find

I_2

  1. I_1=\frac{q}{t}I_1=\frac{20}{10}I_1=2\,\text{А}

    Based on the transferred charge, we determine the initial current.

  2. R=\frac{U_1}{I_1}R=\frac{12}{2}R=6\,\text{Ом}

    We find constant resistance.

  3. I_2=\frac{U_2}{R}I_2=\frac{30}{6}I_2=5\,\text{А}

    We use new voltage.

Answer5\,\text{А}

Position in this set: 12 from 18

Problem #162

Resistance and Ohm's Law

Under tension 18 V through a resistor for 20 s charge passed 60 Cl. What current will be at voltage 24 Q, if the resistance does not change?

Answer options

  1. 8\,\text{А}
  2. 2\,\text{А}
  3. 12\,\text{А}
  4. 4\,\text{А}
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Given
U_1
18\,\text{В}
t
20\,\text{с}
q
60\,\text{Кл}
U_2
24\,\text{В}
Find

I_2

  1. I_1=\frac{q}{t}I_1=\frac{60}{20}I_1=3\,\text{А}

    Based on the transferred charge, we determine the initial current.

  2. R=\frac{U_1}{I_1}R=\frac{18}{3}R=6\,\text{Ом}

    We find constant resistance.

  3. I_2=\frac{U_2}{R}I_2=\frac{24}{6}I_2=4\,\text{А}

    We use new voltage.

Answer4\,\text{А}

Position in this set: 13 from 18

Problem #163

Conductor resistance and rheostat

Wire length 10 m andmherт section 0{,}5 mm². Resistivity 0{,}1 Ohm mm²/m. Find resistance.

Answer options

  1. 4\,\text{Ом}
  2. 2\,\text{Ом}
  3. 1\,\text{Ом}
  4. 6\,\text{Ом}
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Given
l
10\,\text{м}
S
0{,}5\,\text{мм}^{2}
r
0{,}1\,\text{Ом·мм}^{2}\text{/м}
Find

R

  1. R=\rho\frac{l}{S}R=\frac{0{,}1 \cdot 10}{0{,}5}R=2\,\text{Ом}

    Resistivity units are consistent with length and cross-section.

Answer2\,\text{Ом}

Position in this set: 14 from 18

Problem #164

Conductor resistance and rheostat

Wire length 20 m andmherт section 0{,}4 mm². Resistivity 0{,}02 Ohm mm²/m. Find resistance.

Answer options

  1. 2\,\text{Ом}
  2. 0{,}5\,\text{Ом}
  3. 1\,\text{Ом}
  4. 3\,\text{Ом}
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Given
l
20\,\text{м}
S
0{,}4\,\text{мм}^{2}
r
0{,}02\,\text{Ом·мм}^{2}\text{/м}
Find

R

  1. R=\rho\frac{l}{S}R=\frac{0{,}02 \cdot 20}{0{,}4}R=1\,\text{Ом}

    Resistivity units are consistent with length and cross-section.

Answer1\,\text{Ом}

Position in this set: 15 from 18

Problem #165

Conductor resistance and rheostat

Full wire rheostat length 10 m andmherт resistance 20 Ohm. slider includes B chain 3 m wire. Find force current Under tension 12 B on this parts.

Answer options

  1. 4\,\text{А}
  2. 1\,\text{А}
  3. 2\,\text{А}
  4. 6\,\text{А}
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Given
l
10\,\text{м}
R
20\,\text{Ом}
a
3\,\text{м}
U
12\,\text{В}
Find

I

  1. r=R\frac{a}{l}r=\frac{20 \cdot 3}{10}r=6\,\text{Ом}

    The resistance of a homogeneous wire is proportional to its length.

  2. I=\frac{U}{r}I=\frac{12}{6}I=2\,\text{А}

    Ohm's law applies only to the included part.

Answer2\,\text{А}

Position in this set: 16 from 18

Problem #166

Conductor resistance and rheostat

Full wire rheostat length 12 m andmherт resistance 24 Ohm. slider includes B chain 4 m wire. Find force current Under tension 24 B on this parts.

Answer options

  1. 6\,\text{А}
  2. 1{,}5\,\text{А}
  3. 9\,\text{А}
  4. 3\,\text{А}
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Given
l
12\,\text{м}
R
24\,\text{Ом}
a
4\,\text{м}
U
24\,\text{В}
Find

I

  1. r=R\frac{a}{l}r=\frac{24 \cdot 4}{12}r=8\,\text{Ом}

    The resistance of a homogeneous wire is proportional to its length.

  2. I=\frac{U}{r}I=\frac{24}{8}I=3\,\text{А}

    Ohm's law applies only to the included part.

Answer3\,\text{А}

Position in this set: 17 from 18

Problem #167

Conductor resistance and rheostat

Wire with specific resistance 0{,}5 Ohm mm²/m and cross section 0{,}2 mm² should skip current 2 A Under tension 10 B. Find mass this wire, if her density 8 g/cm³. Please note: 1 m·mm² = 1 cm³.

Answer options

  1. 6{,}4\,\text{г}
  2. 1{,}6\,\text{г}
  3. 9{,}6\,\text{г}
  4. 3{,}2\,\text{г}
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Given
r
0{,}5\,\text{Ом·мм}^{2}\text{/м}
S
0{,}2\,\text{мм}^{2}
I
2\,\text{А}
U
10\,\text{В}
d
8\,\text{г/см}^{3}
Find

m

  1. R=\frac{U}{I}R=\frac{10}{2}R=5\,\text{Ом}

    First we determine the required resistance.

  2. l=\frac{RS}{\rho}l=\frac{5 \cdot 0{,}2}{0{,}5}l=2\,\text{м}

    Express the length of the wire.

  3. V=lSV=2 \cdot 0{,}2V=0{,}4\,\text{см}^{3}

    We use the correspondence of units specified in the condition.

  4. m=dVm=8 \cdot 0{,}4m=3{,}2\,\text{г}

    We find mass by density and volume.

Answer3{,}2\,\text{г}

Position in this set: 18 from 18

Problem #168

Conductor resistance and rheostat

Wire with specific resistance 0{,}4 Ohm mm²/m and cross section 0{,}3 mm² should skip current 3 A Under tension 12 B. Find mass this wire, if her density 8 g/cm³. Please note: 1 m·mm² = 1 cm³.

Answer options

  1. 7{,}2\,\text{г}
  2. 14{,}4\,\text{г}
  3. 3{,}6\,\text{г}
  4. 21{,}6\,\text{г}
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Given
r
0{,}4\,\text{Ом·мм}^{2}\text{/м}
S
0{,}3\,\text{мм}^{2}
I
3\,\text{А}
U
12\,\text{В}
d
8\,\text{г/см}^{3}
Find

m

  1. R=\frac{U}{I}R=\frac{12}{3}R=4\,\text{Ом}

    First we determine the required resistance.

  2. l=\frac{RS}{\rho}l=\frac{4 \cdot 0{,}3}{0{,}4}l=3\,\text{м}

    Express the length of the wire.

  3. V=lSV=3 \cdot 0{,}3V=0{,}9\,\text{см}^{3}

    We use the correspondence of units specified in the condition.

  4. m=dVm=8 \cdot 0{,}9m=7{,}2\,\text{г}

    We find mass by density and volume.

Answer7{,}2\,\text{г}

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