GRADE 10 · DYNAMICS
Newton's laws
How forces relate to acceleration and interactions between bodies.
Read the full lesson theory here without an account. In the interactive lesson, the same theory is presented as cards, followed by questions with feedback and practice problems. Your progress is saved.
Understanding step by step
A trolley stops quickly on a rough track but rolls much longer on a smooth one. Must a force keep motion going, or is force needed for something else: changing velocity?
When velocity stays unchanged
Reducing friction lets the trolley keep moving longer after a push. Imagine removing resistance entirely: nothing remains to change its velocity. The persistence of rest or uniform straight-line motion without external influence is called inertia. Frames in which a free body behaves this way are inertial frames. An Earth-based laboratory is approximately inertial in many school experiments; a sharply braking carriage is not a suitable example of this model.
Who acts on whom?
When a hand pushes a trolley, they interact. The effect on the chosen body is described by force \vec F, in newtons. First isolate the trolley mentally: which objects act on it—the hand, Earth, the floor? Add these forces as vectors to obtain the net force \sum\vec F. Opposing effects can balance partly or fully. The trolley's force on the hand is not on this list: it acts on a different recipient.
From force to acceleration
The same trolley can be accelerated more or less strongly. Experiments show that doubling the net force doubles acceleration. Doubling mass at the same force makes velocity change half as fast. Newton's second law combines these relations: \sum\vec F=m\vec a. Mass m, in kg, measures inertia; acceleration \vec a, in m/s², points along the net force, not necessarily along the existing velocity.
Limits of the law
Why not simply take one prominent force and write F=ma? Acceleration comes from all the forces acting together. Here F is the magnitude of their vector sum. We use \sum\vec F=m\vec a for a constant-mass body in an inertial frame, at speeds much smaller than light speed. When fuel leaves a rocket, the chosen body's composition changes; this equation cannot be transferred to it without accounting for mass flow.
What a newton means
The force unit is consistent with mass and acceleration units: 1\,\text{Н}=1\,\text{кг}\cdot\text{м/с}^2. A net force of 1 N gives a 1 kg body acceleration 1 m/s²: its velocity changes by 1 m/s each second. The same force gives a 2 kg body acceleration 0.5 m/s². If the net force falls to zero, acceleration vanishes for finite positive mass, but the velocity already gained remains.
Balanced forces
A book rests on a table: gravity acts, but the support balances it. A trolley can also move at constant velocity with zero net force. In both cases the law gives \vec a=0, so the velocity vector stays constant; rest is the special case of zero initial velocity. Motion alone therefore does not show that the net force points forwards. We must observe the change in velocity.
An interaction pair
Push a wall with your palm: your palm feels a force too. For a hand and trolley, call the hand's force on the trolley \vec F_1 and the trolley's force on the hand \vec F_2. Newton's third law relates them: \vec F_1=-\vec F_2. Their magnitudes are equal and their directions opposite at the same instant. They are two sides of one interaction, not a sequence of action followed by response. Different masses mean equal forces need not give equal accelerations.
Why the trolley accelerates
Why does the trolley accelerate anyway? Only the hand's force from the interaction pair acts on it; the other force acts on the hand. Forces can balance on the same chosen body, so this pair cannot cancel in the trolley's equation. For a system containing person and trolley, the pair becomes internal and cancels in the total; external forces, such as those from the floor, remain. The chosen system changes the force list, not the motion itself.
Work through an example
Horizontal forces of 6 N right and 2 N left act on a 2 kg trolley. Find its acceleration.
Let's look at an example · 1
Choose the trolley and take right as positive.
Let's look at an example · 2
Add force components: ΣFx=6−2=4 Н.
Let's look at an example · 3
By Newton's second law, ax=ΣFx/m=4/2=2 м/с².
Worked example · 4
Check: the net force points right, so acceleration also points right.
Let's check the result
Acceleration is 2 m/s² to the right: each second the rightward velocity component increases by 2 m/s. If the trolley initially moved left, it would first slow down.
Key idea · 1
Force changes velocity. With zero net force, both rest and existing uniform straight-line motion persist.
Key idea · 2
Acceleration increases with net force and decreases with mass; write the equation for a specific body in a chosen reference frame.
Key idea · 3
Interaction forces are equal but act on different bodies. They cannot cancel in the equation for one body.
Where do we go next?
Next we study models for particular forces and conditions for equilibrium.
Basic Concepts
Inertia
The persistence of rest or uniform straight-line motion in an inertial reference frame when the net force is zero.
No net force is needed to maintain uniform motion. A net force is needed to change a body's velocity.
Newton's laws
Basic laws of dynamics that connect the movement of a body with the forces acting on it.
Choose the body, show all forces acting on it, and add them as vectors: the net force determines acceleration.
Physical quantities
Force
FA measure of mechanical interaction between bodies.
Unit: newton · \mathrm{Н}
Net force
\sum FThe vector sum of all forces acting on a body.
Unit: newton · \mathrm{Н}
Lesson formulas
Newton's second law
F=maThe resultant force is equal to the product of mass and acceleration.
Definition of the newton
1\,\mathrm{Н}=1\,\frac{\mathrm{кг}\cdot\mathrm{м}}{\mathrm{с}^2}One newton gives a one-kilogram mass an acceleration of one metre per second squared.
Second law with several forces
\sum\vec{F}=m\vec{a}The vector sum of forces is equal to the product of mass and acceleration.
Newton's third law
\vec{F_1}=-\vec{F_2}The forces of interaction between two bodies are equal in magnitude and opposite in direction.
Test the relationship
Make a prediction first. The button changes the stated quantity; then compare the result and explore other values.
Force, mass and friction
ΣF = F + Fтр; a = ΣF/m; |Fтр| ≤ μmg
The object starts at rest on a horizontal surface; g = 10 m/s². Limiting static and kinetic friction coefficients are taken equal. N = mg.
At F = 6 N and μ = 0, mass increases from 2 to 4 kg. How will a change?
Initial values
Calculated result
- a
- 3 м/с²
- ΣF
- 6 Н
- Fтр
- 0 Н
Explaining the result
Static friction matches the applied force up to μmg, so a small F produces zero acceleration. After slipping starts, acceleration is set by the net force.
Related formulas
The same formulas in the reference, with symbols and units.
Problems on this topic
Statements, answer options and the walkthrough.