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GRADE 7 · BUOYANT FORCE AND FLOATING

Floating objects, ships and balloons

Sinking, rising, equilibrium and average density.

20 minutes5 theory cards
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Understanding step by step

A steel nail sinks, yet a steel ship stays afloat. Archimedes' principle is the same. How does the comparison of forces change when the same material forms a large hollow hull?

Steel nailSteel shipsinksairfloatsSame steel, different behaviour
The nail and ship's hull are made of the same steel, yet the nail sinks and the ship floats. Count the mass and volume of the whole ship, including the air inside.

Compare two forces

Hold an object inside a liquid, then release it from rest. Gravity mg pulls down; buoyant force FА acts up. If FА > mg, the unbalanced force points up and the object starts to rise; if FА < mg, it starts to sink. With equal forces, it can remain at rest. We include only these two forces here: a string, support, significant current or drag would require us to add forces to the diagram.

Release from restSinksRisesFАmgFАmg
Equal-volume objects are fully immersed in the same liquid and released from rest. FА is therefore equal; the heavier object on the left has mg > FА, and the lighter one on the right has mg < FА. Forces are drawn at one point on each object; rotation is not considered.

Average density of the whole object

Cut a solid steel cube, then make a sealed box from the same mass of steel. The mass is nearly unchanged but the external volume is larger, so the box can displace more water. Average density ρт = m/Vвнешний compares total mass with external volume, including sealed cavities; its unit is kg/m³. A ship's mass includes hull, air, equipment and cargo. Steel density alone does not describe the entire ship.

What we count togethercargoair insidesteelρт = total mass : external volumeinclude hull, air and cargoρ of whole ship < ρ of steel
Average density uses the entire mass of hull and cargo divided by external volume, including enclosed air. The ship's average density is therefore lower than that of steel alone.

Density predicts the initial motion

At full immersion, FА = ρжgV and mg = ρтVg. Both expressions contain the same g and external displaced volume V, so comparing forces becomes comparing densities. If ρт < ρж, the released object starts to rise; if ρт > ρж, it starts to sink. Equal densities allow equilibrium inside the liquid. This assumes that the chosen volume really displaces liquid; open cavities that fill with liquid need separate treatment.

Compare with water densityρт < ρжrisesρт = ρжstays at restρт > ρжsinksRelease from rest
Fully immersed objects are released from rest in uniform water. Lower average density means the object starts rising; higher density means it starts sinking. Equal densities allow rest inside the water. Arrows show initial motion after release, not an existing velocity.

Why rising comes to an end

If a light object rises, why does it not fly out of the water? As it emerges through the surface, its immersed volume decreases. FА then decreases until FА = Fтяж. This is the condition for floating at rest. Greater immersion increases support; shallower immersion reduces it. After possible oscillations have died away, the object settles at equilibrium. A momentary equality of forces during motion does not by itself mean the object has stopped.

FАmgFА = mg
The block floats at rest, partly immersed: upward FА equals downward mg. Both forces are drawn at one point to compare magnitudes and directions; rotation is not considered. A lower average block density means a smaller immersed fraction.

How a ship takes on cargo

Put cargo into a boat floating at rest. Its gravitational force increases, so the previous buoyant force is insufficient: the boat sinks deeper, displacing more water until the forces balance again. A hollow hull provides a large displaced volume for a moderate total mass. But the available extra immersion is limited. If water starts entering, the calculation for a dry hull no longer applies: both the system's mass and the volume available to keep water out change.

airairUnloadedLoadedMore cargo, larger Vпогр
The same hollow hull before and after loading. The ship floats at rest in both cases, but cargo increases its total mass. On the right, the hull sits deeper and displaces more water, whose weight balances the loaded ship. Hull size and water level remain unchanged.

A balloon

In air, buoyancy must support everything that rises: the gas inside, envelope, basket and load. To start rising, FА must exceed their combined gravitational force. A light gas reduces mass while keeping a large volume. In a hot-air balloon, heated air expands and some escapes through the open bottom, reducing the mass of air inside the envelope at a given volume. Heating a sealed vessel does not by itself reduce mass; lift depends on the balloon's construction, not simply on being 'hot'.

Gravity acts on every partgasFА from airgasenvelopebasketcargoFА > mg; m is the total mass
For a balloon to rise, air's buoyant force must exceed the combined gravitational force of gas, envelope, basket and load. Light or heated gas reduces total mass at the same volume.

Force and velocity are different

Throw a light object down into water. If buoyancy exceeds gravity, must it immediately move upwards? At first it may continue downwards while slowing, because force changes velocity rather than resetting it at every instant. Its motion may then reverse. That is why the simple rising and sinking rules above refer to release from rest. For an object already moving, comparing forces tells us the direction in which velocity changes.

Already moving downwardsFАmgv downwardsFА > mgVelocity down, acceleration up
The object is already moving downwards, but FА exceeds mg. The resultant force and acceleration currently point upwards, so its downward speed decreases. Forces are drawn at one point to compare directions; rotation is not considered.

What fraction of a block is underwater?

A block of average density 600 kg/m³ floats at rest in water of density 1000 kg/m³. Find the fraction of its volume that is immersed.

Floating at restρт = 600 кг/м³ρводы = 1000 кг/м³What fraction is underwater?
A block of average density 600 kg/m³ floats at rest in water of density 1000 kg/m³. Find its immersed fraction. The block's geometry, water level and data remain unchanged throughout the solution.

Let's look at an example · 1

For floating equilibrium, ρводы·g·Vпогр = m·g. The block's mass is ρт·Vвесь.

Floating at rest: FА = mgρт = 600 кг/м³ρводы = 1000 кг/м³ρводы · g · Vпогр = ρт · g · VвесьCancel the same g
For the same block at rest, FА = mg. Replace mass with ρтVвесь and buoyant force with ρводыgVпогр. The same g cancels on both sides, leaving densities and volumes.

Let's look at an example · 2

Cancelling g gives Vпогр/Vвесь = ρт/ρводы = 600/1000 = 0,6.

Divide the densitiesρт = 600 кг/м³ρводы = 1000 кг/м³Vпогр / Vвесь = 600 / 1000 = 0,6
The apparatus and given data stay unchanged. The ratio of immersed volume to total volume equals the density ratio: 600/1000 = 0,6.

Let's look at an example · 3

Six tenths of the volume displaces water whose weight equals the block's gravitational force.

What 0.6 meansρт = 600 кг/м³ρводы = 1000 кг/м³0,60,460% of the volume underwater40% of the volume above water
The same rectangular block has constant cross-sectional area, so 60% of its height corresponds to 60% of its volume. The underwater fraction is 0.6; the fraction above is 0.4. Brackets span the respective parts; the displaced water weighs as much as the block.

Let's check the result

60% of the volume is underwater. This part displaces water with the same mass as the entire block; the remaining 40% of the volume is above the surface.

Key idea · 1

Floating depends on comparing the entire system's gravitational force with buoyancy, not just naming its material.

Key idea · 2

For floating at rest, FА = mg; adding cargo requires more water to be displaced.

Key idea · 3

Forces determine changes in velocity. A rule for starting to rise from rest does not instantly specify the direction of existing motion.

Where do we go next?

Forces transfer energy when lifting loads. The next lesson introduces mechanical work and power.

Basic Concepts

3 concepts

Condition for floating equilibrium

A floating object is in equilibrium when buoyant force equals gravitational force in magnitude.

If an object's average density is lower than the liquid's density, it rises and floats partly immersed.

Sinking and rising

If only gravity and buoyancy act on an object released from rest, it starts sinking when gravity is greater and rising when buoyancy is greater.

Comparing forces tells us how velocity changes. An object already moving can travel against the resultant force for a while. Adjusting ballast or envelope volume changes average density, controlling the buoyancy of craft and balloons.

Ships and balloon flight

Hollow ships and balloons displace a large volume to obtain the buoyant force they need.

A steel ship floats because the average density of its hull with air is low; a balloon rises in the atmosphere.

Physical quantities

1 magnitude

Average object density

\rho_{\text{т}}

The ratio of an object's total mass to its external volume.

Unit: kilogram per cubic meter · \frac{\mathrm{кг}}{\mathrm{м}^3}

Lesson formulas

1 formula

Equilibrium of a floating object

F_A = F_{\text{тяж}}

When floating at rest, buoyant force equals gravitational force.

Test the relationship

Make a prediction first. The button changes the stated quantity; then compare the result and explore other values.

Floating and density

Fₐ = ρжgVпогр; mg = ρтgV; Vпогр/V = min(1, ρт/ρж)

Uniform object in water of density 1000 kg/m³, g = 10 m/s². No surface tension. A sinking object is shown fully submerged before touching the bottom, not in equilibrium.

The volume of an object with the same density increases from 2 to 4 L. How will the submerged fraction change?

Your prediction

Initial values

Show vectors
Fₐmg

Calculated result

Vпогр/V
60 %
Fₐ
12 Н
mg
12 Н

Floats: Fₐ = mg

Explaining the result

For floating, Fₐ = mg: volume cancels from the density ratio. At ρт > ρж, even the maximum buoyant force is smaller than gravity.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.