GRADE 7 · BUOYANT FORCE AND FLOATING
Floating objects, ships and balloons
Sinking, rising, equilibrium and average density.
Read the full lesson theory here without an account. In the interactive lesson, the same theory is presented as cards, followed by questions with feedback and practice problems. Your progress is saved.
Understanding step by step
A steel nail sinks, yet a steel ship stays afloat. Archimedes' principle is the same. How does the comparison of forces change when the same material forms a large hollow hull?
Compare two forces
Hold an object inside a liquid, then release it from rest. Gravity mg pulls down; buoyant force FА acts up. If FА > mg, the unbalanced force points up and the object starts to rise; if FА < mg, it starts to sink. With equal forces, it can remain at rest. We include only these two forces here: a string, support, significant current or drag would require us to add forces to the diagram.
Average density of the whole object
Cut a solid steel cube, then make a sealed box from the same mass of steel. The mass is nearly unchanged but the external volume is larger, so the box can displace more water. Average density ρт = m/Vвнешний compares total mass with external volume, including sealed cavities; its unit is kg/m³. A ship's mass includes hull, air, equipment and cargo. Steel density alone does not describe the entire ship.
Density predicts the initial motion
At full immersion, FА = ρжgV and mg = ρтVg. Both expressions contain the same g and external displaced volume V, so comparing forces becomes comparing densities. If ρт < ρж, the released object starts to rise; if ρт > ρж, it starts to sink. Equal densities allow equilibrium inside the liquid. This assumes that the chosen volume really displaces liquid; open cavities that fill with liquid need separate treatment.
Why rising comes to an end
If a light object rises, why does it not fly out of the water? As it emerges through the surface, its immersed volume decreases. FА then decreases until FА = Fтяж. This is the condition for floating at rest. Greater immersion increases support; shallower immersion reduces it. After possible oscillations have died away, the object settles at equilibrium. A momentary equality of forces during motion does not by itself mean the object has stopped.
How a ship takes on cargo
Put cargo into a boat floating at rest. Its gravitational force increases, so the previous buoyant force is insufficient: the boat sinks deeper, displacing more water until the forces balance again. A hollow hull provides a large displaced volume for a moderate total mass. But the available extra immersion is limited. If water starts entering, the calculation for a dry hull no longer applies: both the system's mass and the volume available to keep water out change.
A balloon
In air, buoyancy must support everything that rises: the gas inside, envelope, basket and load. To start rising, FА must exceed their combined gravitational force. A light gas reduces mass while keeping a large volume. In a hot-air balloon, heated air expands and some escapes through the open bottom, reducing the mass of air inside the envelope at a given volume. Heating a sealed vessel does not by itself reduce mass; lift depends on the balloon's construction, not simply on being 'hot'.
Force and velocity are different
Throw a light object down into water. If buoyancy exceeds gravity, must it immediately move upwards? At first it may continue downwards while slowing, because force changes velocity rather than resetting it at every instant. Its motion may then reverse. That is why the simple rising and sinking rules above refer to release from rest. For an object already moving, comparing forces tells us the direction in which velocity changes.
What fraction of a block is underwater?
A block of average density 600 kg/m³ floats at rest in water of density 1000 kg/m³. Find the fraction of its volume that is immersed.
Let's look at an example · 1
For floating equilibrium, ρводы·g·Vпогр = m·g. The block's mass is ρт·Vвесь.
Let's look at an example · 2
Cancelling g gives Vпогр/Vвесь = ρт/ρводы = 600/1000 = 0,6.
Let's look at an example · 3
Six tenths of the volume displaces water whose weight equals the block's gravitational force.
Let's check the result
60% of the volume is underwater. This part displaces water with the same mass as the entire block; the remaining 40% of the volume is above the surface.
Key idea · 1
Floating depends on comparing the entire system's gravitational force with buoyancy, not just naming its material.
Key idea · 2
For floating at rest, FА = mg; adding cargo requires more water to be displaced.
Key idea · 3
Forces determine changes in velocity. A rule for starting to rise from rest does not instantly specify the direction of existing motion.
Where do we go next?
Forces transfer energy when lifting loads. The next lesson introduces mechanical work and power.
Basic Concepts
Condition for floating equilibrium
A floating object is in equilibrium when buoyant force equals gravitational force in magnitude.
If an object's average density is lower than the liquid's density, it rises and floats partly immersed.
Sinking and rising
If only gravity and buoyancy act on an object released from rest, it starts sinking when gravity is greater and rising when buoyancy is greater.
Comparing forces tells us how velocity changes. An object already moving can travel against the resultant force for a while. Adjusting ballast or envelope volume changes average density, controlling the buoyancy of craft and balloons.
Ships and balloon flight
Hollow ships and balloons displace a large volume to obtain the buoyant force they need.
A steel ship floats because the average density of its hull with air is low; a balloon rises in the atmosphere.
Physical quantities
Average object density
\rho_{\text{т}}The ratio of an object's total mass to its external volume.
Unit: kilogram per cubic meter · \frac{\mathrm{кг}}{\mathrm{м}^3}
Lesson formulas
Equilibrium of a floating object
F_A = F_{\text{тяж}}When floating at rest, buoyant force equals gravitational force.
Test the relationship
Make a prediction first. The button changes the stated quantity; then compare the result and explore other values.
Floating and density
Fₐ = ρжgVпогр; mg = ρтgV; Vпогр/V = min(1, ρт/ρж)
Uniform object in water of density 1000 kg/m³, g = 10 m/s². No surface tension. A sinking object is shown fully submerged before touching the bottom, not in equilibrium.
The volume of an object with the same density increases from 2 to 4 L. How will the submerged fraction change?
Initial values
Calculated result
- Vпогр/V
- 60 %
- Fₐ
- 12 Н
- mg
- 12 Н
Floats: Fₐ = mg
Explaining the result
For floating, Fₐ = mg: volume cancels from the density ratio. At ρт > ρж, even the maximum buoyant force is smaller than gravity.
Related formulas
The same formulas in the reference, with symbols and units.
Problems on this topic
Statements, answer options and the walkthrough.