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GRADE 7 · FORCES

Friction force

Static friction, kinetic friction and rolling resistance in technology and everyday life.

18 minutes7 theory cards
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Understanding step by step

Pull a cupboard gently: it does not move. Pull harder: it still stays put, then begins to slide. Why does friction initially seem to change with our pulling force? And why could we not walk normally without friction?

A gentle pushA stronger pushcupboard stays stillfriction equals the pushcupboard starts movingstatic friction was insufficientFriction behaves differently
A gentle push does not move the cupboard because static friction keeps it in place. A stronger push gets it moving, after which it slides.

Before sliding starts

If the cupboard stays still under a horizontal pull, what balances that pull? The floor resists relative sliding between the surfaces in contact. This is static friction. With a small pull, its magnitude equals the pull and its direction is opposite. Increase the pull within a certain range and friction increases too. But this adjustment has a limit. Once the force needed for equilibrium exceeds that limit, sliding starts.

PushFrictionv = 0
Under a small push, static friction balances the applied force and the block stays in place. Static friction varies from zero up to a limiting value.

Friction can help

Imagine a perfectly slippery floor. Your foot tries to push backwards but slips, barely accelerating you forwards. On an ordinary floor, the foot does not slip while pushing off: it pushes the ground backwards, and static friction from the ground pushes the foot forwards. So ‘friction always opposes the object's motion’ is wrong. Ask how the contacting surfaces slide, or would tend to slide, relative to each other.

What happens beneath the shoe?forwardon the ground: backwardson the foot: forwardsThe forces act on different objects
This shows the rear foot pushing off: the shoe pushes the ground backwards, and static friction from the ground pushes that shoe forwards. The equal opposite forces act on different objects at the same contact. The other foot is moving above the ground.

When an object slides

Now the cupboard slides right over a stationary floor. Kinetic friction from the floor acts left on the cupboard, opposing relative sliding; its magnitude is measured in newtons. But put a block on a belt moving right and slipping underneath it: friction can accelerate the block to the right. The direction depends on the relative motion of the surfaces, not merely on the block's velocity relative to the room.

NFтрvSurfaces in contact
The block slides right relative to the table, while friction acts left. The normal force N is perpendicular to the table. For kinetic friction, Fтр = μN.

How strongly are the surfaces pressed together?

Press a sliding eraser harder against the table: it usually becomes harder to pull. We describe the contact loading using the normal force N, the force the support exerts perpendicular to its surface. Here N denotes a force; its unit is the newton. On a horizontal table, with no other vertical forces or acceleration, N = mg. Extra downward pressure increases N. An inclined support or other actions require a separate force analysis.

Resting on the surfaceAn extra downward pushNN = mglarger Ngreater contact loadingN is perpendicular to the surface
The normal force is perpendicular to the surface and indicates how strongly the object is pressed against it. An additional downward push increases the normal force.

Calculate kinetic friction

Experiments with dry surfaces often give the approximate relation Fтр = μN for kinetic friction. The dimensionless coefficient μ depends on the pair of materials and their surface condition. At fixed μ, doubling N doubles friction; lowering μ reduces friction at the same contact loading. The formula separates two ways to change resistance: change the surfaces or how strongly they are pressed together. It is an experimental model, not an exact law for every contact and speed.

Fтр = μ · N, μ = 0,2N = 20 НN = 40 НFтр = 4 НFтр = 8 НBoth blocks slide rightAt the same μ: N × 2 → Fтр × 2
In the dry-sliding model, friction is proportional to normal force. At fixed coefficient, doubling the contact loading doubles friction too.

The model's limits

Does a block at rest with no horizontal action experience friction μN simply because it touches the table? No: there is no horizontal force to balance, and static friction can be zero. Here Fтр = μN applies to sliding. Apparent contact area does not enter this simple model directly: turning the block onto another face need not change friction at the same N and μ. Real surfaces can behave beyond this approximation.

No horizontal pullDifferent contact areaFтр = 0the formula μNdoes not apply herevvflaton edgesame μ and Nsame frictionArea does not enter this simple model
On the left, the block rests with no horizontal action and zero friction. On the right, the same block slides on different faces. With the same μ and N, the simple model predicts the same friction despite the different contact areas.

Why use wheels?

Put a load on wheels instead of dragging it across the floor. Its whole underside no longer has to slide continuously, so transport is usually easier. However, the wheel and support deform slightly during rolling, and some of the energy spent is not returned to motion. This produces rolling resistance, usually smaller than kinetic friction under comparable conditions. Grip between wheel and road is still needed: without it, accelerating, braking and turning are difficult.

vvSlidingRolling
The same load moves right over the same surface. Blue arrows indicate motion; red arrows compare total resistance qualitatively. Under comparable conditions, rolling usually requires less pull than sliding.

Friction on a sliding box

A box is sliding; N = 60 Н, μ = 0,25. Find the friction force.

The box slides across the floorvN = 60 Нμ = 0,25Friction force — ?
A box slides across a surface with N = 60 Н and μ = 0,25. Find the friction force. The diagram chooses rightwards motion, and keeps that direction through every step.

Let's look at an example · 1

Sliding is already occurring, so the model Fтр = μN applies.

Choose the modelvN = 60 Нμ = 0,25There is relative slidingApply Fтр = μN
The object moves relative to the surface, so this is kinetic friction and the approximate model applies. It would not apply to a body at rest relative to the surface.

Let's look at an example · 2

Fтр = 0,25·60 Н = 15 Н. The coefficient is dimensionless, so the result is in newtons.

Substitute into the formulavN = 60 Нμ = 0,25Fтр = 0,25 · 60 Н = 15 Н
Zero point two five multiplied by sixty newtons gives fifteen. The coefficient is dimensionless, so the answer stays in newtons.

Let's look at an example · 3

The force opposes the box's motion relative to the surface.

Opposite to slidingvN = 60 Нμ = 0,25Fтр = 15 НleftFriction resists relative sliding
The box slides right relative to the floor, so friction acts left on it, opposing relative sliding between the surfaces.

Let's check the result

15 Н opposite to relative sliding.

Key idea · 1

Friction opposes relative sliding or the tendency to slide. It can accelerate an object.

Key idea · 2

Static friction adjusts to other forces up to a limit and can be zero.

Key idea · 3

Fтр = μN approximates dry sliding. First establish the type of contact and the normal force.

Where do we go next?

The same force has different effects over large and small areas. This leads us to pressure.

Basic Concepts

3 concepts

Static friction

A force that prevents the onset of relative sliding of contacting surfaces.

It is static friction that allows the foot to push off the ground without slipping and keeps the object on an inclined surface.

Rolling resistance

Resistance to a rolling object's motion, usually smaller than kinetic friction under the same conditions.

Wheels reduce losses during transportation, but friction remains necessary for acceleration, braking and steering.

Kinetic friction

A contact force that opposes relative sliding between surfaces.

In the simple model, its magnitude depends on the materials, surface condition and normal loading, but not directly on contact area.

Physical quantities

3 quantities

Friction force

F_{\text{тр}}

The force of resistance to the relative movement of contacting surfaces.

Unit: newton · \mathrm{Н}

Coefficient of friction

\mu

A dimensionless property of a pair of contacting surfaces.

Unit: dimensionless quantity

Normal force

N

The force a support exerts on an object perpendicular to the surface.

Unit: newton · \mathrm{Н}

Lesson formulas

1 formula

Kinetic friction

F_{\text{тр}} = \mu N

Kinetic friction equals the coefficient of friction multiplied by the normal force.

Conditions: A model of dry sliding on a horizontal or otherwise specified support.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.