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GRADE 7 · FORCES

Elasticity and net force

Deformation, Hooke's law, force meters and adding forces along a straight line.

24 minutes9 theory cards
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Understanding step by step

Hang a load from a spring. The spring stretches and settles at a new length. Why does it not keep stretching forever? And how can its extension tell us the force when Earth also acts on the load?

A spring with and without a loadnatural lengthloadlongerload removedsame lengthElastic deformation disappears when unloaded
The spring lengthens under a load, then returns to its original length when the load is removed. This repeatable recovery lets us measure force from extension.

A change of shape

Squeeze a rubber ball, then bend a soft wire, and let go. The ball usually regains its shape, while the wire may stay bent. A change in an object's shape or size is deformation. If the change disappears when the load is removed, it is elastic deformation. The part that remains is plastic, or permanent, deformation. A real object may deform elastically at first, then acquire a permanent change under a larger load.

ElasticPlasticstraightenedstays bentElastic deformation disappears;plastic deformation remains
A thin strip straightens when the load is removed, while a bent wire stays bent. The first deformation is elastic; the second is plastic.

What does extension measure?

A spring starts with length l₀ and has length l after stretching. Does its response depend on its whole length or on how much that length changed? What matters is the extension Δl = l − l₀, measured in metres. The elastic restoring force acts to reduce deformation: a stretched spring pulls its ends towards each other. In its original undeformed state Δl = 0, but the full length is not zero. Full length cannot replace extension.

Δl is not the full lengthl₀ = 8 смl = 11 смΔlFупрΔl = 11 − 8 = 3 см
Extension is the new length minus the original length: here 11 − 8 = 3 см. The red bracket shows only that increase. The spring exerts an upward restoring force on the load, tending to restore its original length.

One spring, different loads

Add small loads to the same spring. Within a certain range, doubling the load doubles the extension. To compare springs, define the spring constant k as restoring force divided by extension in that linear range. Its unit is N/m. A stiffer spring needs more force for the same extension; under the same force, it stretches less. The constant describes the spring, including both its material and its construction.

One spring, two experimentsunloaded end positionΔl2ΔlF2FFупр = kΔl
Doubling the extension of the same spring doubles its restoring force: Fупр = kΔl. The dashed line marks the unloaded end position; the brackets show Δl and 2Δl. The law applies in the linear elastic range.

Hooke's law for force magnitude

Write the observed proportionality as Fупр = kΔl: Hooke's law for the magnitude of force during stretching in the linear elastic range. Multiplying k in N/m by Δl in m gives newtons. Double the extension in this range and the force doubles; at zero deformation the force is zero. We cannot extend this straight-line relationship to arbitrarily large loads. Even elastic recovery does not guarantee that force is proportional to extension.

Fупр = k · ΔlunloadedΔlk = 50 Н/мΔl = 0,1 мFупр = 50 · 0,1 = 5 Н
In this example the spring constant is 50 N/m and the extension is 0.1 m. The dashed line marks the unloaded end; the bracket shows the added length. Within the range of Hooke's law, the force is 5 N.

How a force meter works

If the same force always produces the same extension, the spring can become a measuring instrument. Apply known forces and mark the pointer positions in newtons, then compare an unknown force with those marks. This is a spring force meter. Check zero before reading and wait for a steady indication. Exceeding its measuring range may permanently deform the spring, making the old scale inaccurate.

Mark the scale, then take a reading01 Н2 Н3 Н2 Нknown loadcheck zeroand the scale limit
First hang known loads from the spring and mark the pointer positions. Then use these marks to read an unknown force, after checking zero and keeping within the measuring range.

Consider all the forces

A load on a spring experiences gravity downwards and spring force upwards. Their combined effect determines how its motion changes. The net force R is the vector sum of the forces acting on one chosen object, measured in newtons. Here we either model the object as a point particle, ignoring size and rotation, or consider forces along one line. We cannot add forces on different objects this way: they change the motion of different objects.

What acts on the block?gravitysupport force NpullfrictionArrow tails share one point
Gravity, support force, pulling force and friction act on the block. To add them, the arrow tails are drawn at one marked point; rotation is not considered. The vertical forces balance, while the pull to the right exceeds friction.

Forces in the same direction

Two people pull the same trolley along one line in the same direction with forces of 2 N and 3 N. The actions reinforce each other: R = F₁ + F₂ = 5 Н, in the same direction. If one force becomes zero, the other remains; doubling both doubles the result. Adding magnitudes this way works only when the directions agree. For forces at an angle, simply adding numbers is not enough.

Add arrows along a straight line2 Н3 НR = 5 НR = 2 + 3 = 5 Н to the right
Forces of 2 and 3 N act on the same object to the right. To construct their sum, move the second arrow's tail to the first arrow's tip. The lower arrow shows the net force, 5 N to the right, on the same scale.

Forces in opposite directions

What if the trolley is pulled in opposite directions? A 3 N force to the left cancels part of the 7 N force to the right, leaving R = 4 Н to the right. The magnitude is the larger force minus the smaller, and the direction is that of the larger force. Equal opposite forces along one line give R = 0. Inertia then means unchanged velocity, not necessarily a stop. Separate lines of action can still cause rotation, which this simple model does not describe.

Opposite directions7 Н3 НR = 4 Н5 Н5 НEqual opposite forces give R = 0
Opposite forces of 7 and 3 N leave 4 N to the right. The net-force arrow is drawn separately below the upper block, using the same scale. In the lower case, the forces of 5 and 5 N cancel.

A stretched spring

A spring of constant 100 N/m lengthens from 10 to 12 cm within the range of Hooke's law. Find the restoring force.

From 10 см to 12 см10 см12 смk = 100 Н/мRestoring force — ?
A spring of constant one hundred newtons per metre lengthens from ten to twelve centimetres within the range of Hooke's law. Find its restoring force.

Let's look at an example · 1

First find the extension: 12 − 10 = 2 см = 0,02 м.

Extension is the difference in lengths10 см12 смk = 100 Н/мΔlΔl = 12 − 10 = 2 смthis is 0,02 м
Subtract the original length from the new length to obtain two centimetres. Substitute this extension into the formula after converting it to metres.

Let's look at an example · 2

Then Fупр = kΔl = 100·0,02 = 2 Н.

Multiply spring constant by extension10 см12 смk = 100 Н/мΔlFупр = 100 · 0,02 = 2 Н
Multiply the spring constant of one hundred newtons per metre by the extension of two hundredths of a metre to obtain a restoring force of two newtons.

Let's look at an example · 3

The force acts to restore the original length. Do not substitute the full 12 cm into the formula.

Towards the original length10 см12 смk = 100 Н/мΔlFупрFупр = 2 Н: the spring pulls the load upwardsΔl = 0,02 м; full length 0,12 м
The same spring exerts an upward restoring force of 2 N on the load, tending to restore its original length. The arrow starts where the load is attached. Use the extension of 0.02 m, not the full length of 0.12 m, in the formula.

Let's check the result

The restoring force has a magnitude of 2 N.

Key idea · 1

A spring responds to a change in length. Hooke's law uses extension, not full length.

Key idea · 2

The proportionality Fупр = kΔl is established experimentally and applies only in the linear elastic range.

Key idea · 3

The combined effect depends on force directions and which object they act on. A zero net force preserves the existing velocity.

Where do we go next?

Friction is often among the forces on a moving object. Next we will explore when it hinders motion and when it helps.

Basic Concepts

3 concepts

Deformation

A change in an object's shape or size under external forces is called deformation.

Elastic deformation disappears when the load is removed; plastic deformation leaves a noticeable permanent change.

Hooke's law

In the linear elastic range, the magnitude of the restoring force is proportional to the magnitude of the change in length.

The spring constant relates force to change in length. Recovering the original shape does not guarantee linearity: elastic deformation can extend beyond the range of Hooke's law.

Net force

A single force that replaces the combined effect of several forces and produces the same change in motion.

Add forces pointing in the same direction; subtract opposite forces. The result points in the direction of the larger force.

Physical quantities

4 quantities

Elastic restoring force

F_{\text{упр}}

A force arising from deformation that acts to restore the shape.

Unit: newton · \mathrm{Н}

Extension

\Delta l

The change in length of an elastically deformed object.

Unit: metre · \mathrm{м}

Spring constant

k

The constant of proportionality between restoring force and extension.

Unit: newton per metre · \frac{\mathrm{Н}}{\mathrm{м}}

Net force

R

A force equivalent to the combined action of several forces.

Unit: newton · \mathrm{Н}

Lesson formulas

2 formulas

Hooke's law for force magnitude

F_{\text{упр}} = k|\Delta l|

Restoring force magnitude equals the spring constant multiplied by the magnitude of the change in length.

Conditions: Small deformation in the linear elastic range; the force opposes the deformation.

Forces in the same direction

R = F_1 + F_2

For forces in the same direction, the net force magnitude is the sum of their magnitudes.

Related formulas

The same formulas in the reference, with symbols and units.

Problems on this topic

Statements, answer options and the walkthrough.